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Prove the identity ( 3theta - 3theta)/(1 - 2 2theta) = theta + theta. Identify any errors in the solution.

Mathematics

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Answer

You're working on proving the identity cos⁡3θ−sin⁡3θ1−2sin⁡2θ=cos⁡θ+sin⁡θ\frac{\cos 3\theta - \sin 3\theta}{1 - 2\sin 2\theta} = \cos \theta + \sin \theta. Let's break down your steps to find the error.

Your initial steps are correct:

  1. You correctly expanded cos⁡3θ\cos 3\theta and sin⁡3θ\sin 3\theta using the triple angle formulas: cos⁡3θ=4cos⁡3θ−3cos⁡θ\cos 3\theta = 4\cos^3\theta - 3\cos\theta sin⁡3θ=3sin⁡θ−4sin⁡3θ\sin 3\theta = 3\sin\theta - 4\sin^3\theta And the denominator using the double angle formula: $1 - 2
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