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If 10 workers can complete a job in 10 days, how many days would it take 15 workers? Assume indirect proportion.

Mathematics

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Step-by-step solution

4 steps
  1. Identify the given values and the type of proportion.

    This is an inverse proportion problem because as the number of workers increases, the number of days required to complete the job decreases.
    Given:
    Initial workers (W1W_1) = 10 workers
    Initial days (D1D_1) = 10 days
    New workers (W2W_2) = 15 workers
    New days (D2D_2) = ?

  2. Set up the inverse proportion equation.

    For inverse proportion, the product of the number of workers and the number of days is constant.

    W1×D1=W2×D2W_1 \times D_1 = W_2 \times D_2
  3. Substitute the known values into the equation.

    10 workers×10 days=15 workers×D210 \text{ workers} \times 10 \text{ days} = 15 \text{ workers} \times D_2
  4. Solve for D2D_2.

    100=15×D2100 = 15 \times D_2 D2=10015D_2 = \frac{100}{15} D2=203D_2 = \frac{20}{3} D2=623 daysD_2 = 6\frac{2}{3} \text{ days}

    It would take 15 workers \boxed{\text{6\frac{2}{3} days}} to complete the job.

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