If 19xN = 2n - 5m, Find A) 7x1 B) 3 x 4/7 C) -4x3 D) 2/5 x 4/7

Mathematics
If 19xN = 2n - 5m, Find A) 7x1 B) 3 x 4/7 C) -4x3 D) 2/5 x 4/7

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: Given the binary operation: M×N=2N−5MM \times N = 2N - 5M. We need to evaluate this operation for the following expressions:

a) Evaluate 7×17 \times 1

Step 1: Identify the values for MM and NN. For 7×17 \times 1, we have M=7M = 7 and N=1N = 1.

Step 2: Substitute these values into the operation definition. 7×1=2(1)−5(7)7 \times 1 = 2(1) - 5(7)

Step 3: Perform the multiplications. 7×1=2−357 \times 1 = 2 - 35

Step 4: Perform the subtraction. 7×1=−337 \times 1 = \boxed{-33}

b) Evaluate 3×473 \times \frac{4}{7}

Step 1: Identify the values for MM and NN. For 3×473 \times \frac{4}{7}, we have M=3M = 3 and N=47N = \frac{4}{7}.

Step 2: Substitute these values into the operation definition. 3×47=2(47)−5(3)3 \times \frac{4}{7} = 2\left(\frac{4}{7}\right) - 5(3)

Step 3: Perform the multiplications. 3×47=87−153 \times \frac{4}{7} = \frac{8}{7} - 15

Step 4: Convert to a common denominator and subtract. 3×47=87−15×773 \times \frac{4}{7} = \frac{8}{7} - \frac{15 \times 7}{7} 3×47=87−10573 \times \frac{4}{7} = \frac{8}{7} - \frac{105}{7} 3×47=8−10573 \times \frac{4}{7} = \frac{8 - 105}{7} 3×47=−9773 \times \frac{4}{7} = \boxed{-\frac{97}{7}}

c) Evaluate −4×3-4 \times 3

Step 1: Identify the values for MM and NN. For −4×3-4 \times 3, we have M=−4M = -4 and N=3N = 3.

Step 2: Substitute these values into the operation definition. −4×3=2(3)−5(−4)-4 \times 3 = 2(3) - 5(-4)

Step 3: Perform the multiplications. −4×3=6−(−20)-4 \times 3 = 6 - (-20) −4×3=6+20-4 \times 3 = 6 + 20

Step 4: Perform the addition. −4×3=26-4 \times 3 = \boxed{26}

d) Evaluate 25×47\frac{2}{5} \times \frac{4}{7}

Step 1: Identify the values for MM and NN. For 25×47\frac{2}{5} \times \frac{4}{7}, we have M=25M = \frac{2}{5} and N=47N = \frac{4}{7}.

Step 2: Substitute these values into the operation definition. 25×47=2(47)−5(25)\frac{2}{5} \times \frac{4}{7} = 2\left(\frac{4}{7}\right) - 5\left(\frac{2}{5}\right)

Step 3: Perform the multiplications. 25×47=87−105\frac{2}{5} \times \frac{4}{7} = \frac{8}{7} - \frac{10}{5} 25×47=87−2\frac{2}{5} \times \frac{4}{7} = \frac{8}{7} - 2

Step 4: Convert to a common denominator and subtract. 25×47=87−2×77\frac{2}{5} \times \frac{4}{7} = \frac{8}{7} - \frac{2 \times 7}{7} 25×47=87−147\frac{2}{5} \times \frac{4}{7} = \frac{8}{7} - \frac{14}{7} 25×47=8−147\frac{2}{5} \times \frac{4}{7} = \frac{8 - 14}{7} 25×47=−67\frac{2}{5} \times \frac{4}{7} = \boxed{-\frac{6}{7}}

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