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If A's income is 24% less than B's income, by what percentage is B's income more than A's income?

Mathematics

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Answer

(d) 60019%\text{(d) } \frac{600}{19}\%

Step-by-step solution

4 steps

  1. Assume B's income.

    Let B's income be 100.

  2. Calculate A's income.

    A's income is 24% less than B's income.

    A’s income=100−(24% of 100)=100−24=76\text{A's income} = 100 - (24\% \text{ of } 100) = 100 - 24 = 76

  3. Calculate the difference between B's and A's income.

    Difference=B’s income−A’s income=100−76=24\text{Difference} = \text{B's income} - \text{A's income} = 100 - 76 = 24

  4. Calculate the percentage by which B's income is more than A's income.

    To find how much B's income is more than A's income in percentage, we use A's income as the base.

    Percentage more=DifferenceA’s income×100%\text{Percentage more} = \frac{\text{Difference}}{\text{A's income}} \times 100\% Percentage more=2476×100%\text{Percentage more} = \frac{24}{76} \times 100\% Percentage more=6×419×4×100%=619×100%=60019%\text{Percentage more} = \frac{6 \times 4}{19 \times 4} \times 100\% = \frac{6}{19} \times 100\% = \frac{600}{19}\%

    Comparing this with the given options, option (d) is 60019%\frac{600}{19}\%.

    The final answer is (d) 60019%\text{(d) } \frac{600}{19}\%.

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