A's income is 28% more than B's. C's income is 25% less than the sum of A's and B's income. By what…

Question

A's income is 28% more than B's. C's income is 25% less than the sum of A's and B's income. By what percentage is C's income more than A's income?

ScanSolve AI Tutor · Accepted Answer

Step 1: Assume a value for B's income. Let B's income be 100. Step 2: Calculate A's income. A is 28% more than B. A's income = 100 + (0.28 × 100) = 100 + 28 = 128 Step 3: Calculate the sum of A's and B's income. Sum of A and B = A's income + B's income = 128 + 100 = 228 Step 4: Calculate C's income. C is 25% less than the sum of A and B. C's income = 228 − (0.25 × 228) = 228 − 57 = 171 Step 5: Calculate the percentage by which C's income is more than A's income. To find how much C's income is more than A's income in percentage, we use A's income as the base. Difference = C's income − A's income = 171 − 128 = 43; Percentage more = DifferenceA's income × 100%; Percentage more = 43/128 × 100%; Percentage more = 4300/128% Percentage more ≈ 33.59375% Rounding to one decimal place, this is 33.6%. Comparing this with the given options, option (d) is 33.6%. The final answer is (d) 33.6%.

A's income is 28% more than B's. C's income is 25% less than the sum of A's and B's income. By what percentage is C's income more than A's income?

Answer

Step-by-step solution

Assume a value for B's income.

Calculate A's income.

Calculate the sum of A's and B's income.

Calculate C's income.

Calculate the percentage by which C's income is more than A's income.

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