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If m = (tb2)/xy + t, express t in terms of m, b, x and y.

Mathematics

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Answer

A. 54\text{A. } \frac{5}{4}

Step-by-step solution

4 steps

To calculate 1α+1β\frac{1}{\alpha} + \frac{1}{\beta} for the given quadratic equation 2x2−10x+8=02x^2 - 10x + 8 = 0, we first find the sum and product of the roots.

  1. Identify the coefficients of the quadratic equation.

    For a quadratic equation ax2+bx+c=0ax^2 + bx + c = 0, we have:
    a=2a = 2
    b=−10b = -10
    c=8c = 8

  2. Calculate the sum of the roots (α+β\alpha + \beta).

    The sum of the roots is given by the formula α+β=−ba\alpha + \beta = -\frac{b}{a}.

    α+β=−−102=102=5\alpha + \beta = -\frac{-10}{2} = \frac{10}{2} = 5
  3. Calculate the product of the roots (αβ\alpha \beta).

    The product of the roots is given by the formula αβ=ca\alpha \beta = \frac{c}{a}.

    αβ=82=4\alpha \beta = \frac{8}{2} = 4
  4. Simplify the expression 1α+1β\frac{1}{\alpha} + \frac{1}{\beta} and substitute the values.

    To add the fractions, find a common denominator:

    1α+1β=βαβ+ααβ=α+βαβ\frac{1}{\alpha} + \frac{1}{\beta} = \frac{\beta}{\alpha \beta} + \frac{\alpha}{\alpha \beta} = \frac{\alpha + \beta}{\alpha \beta}

    Now, substitute the values found in Step 2 and Step 3:

    α+βαβ=54\frac{\alpha + \beta}{\alpha \beta} = \frac{5}{4}

    The calculated value is 54\frac{5}{4}. Comparing this with the given options, it matches option A.

    The final answer is A. 54\text{A. } \frac{5}{4}.

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