Step 1: Identify the universal set and the given subsets.
The universal set is U={1,2,3,4,5,6,7,8,9,10}.
The given subsets are:
X={2,3,4,6}
Y={1,3,4,5,8,10}
Z={1,3,5}
Step 2: Calculate the intersections and unique elements for the Venn diagram.
First, observe that all elements of Z are also in Y, so Z is a subset of Y (Z⊂Y). This simplifies the Venn diagram structure, as the circle for Z will be entirely inside the circle for Y.
Calculate intersections:
X∩Y={3,4}
X∩Z={3}
Y∩Z={1,3,5} (Since Z⊂Y, this is simply Z)
X∩Y∩Z={3}
Calculate elements for each distinct region:
• Elements in X∩Y∩Z: {3}
• Elements in X∩Y but not in Z: (X∩Y)∖Z={3,4}∖{1,3,5}={4}
• Elements in Y∩Z but not in X: (Y∩Z)∖X={1,3,5}∖{2,3,4,6}={1,5}
• Elements in X only: X∖(Y∪Z)={2,3,4,6}∖({1,3,4,5,8,10}∪{1,3,5})={2,3,4,6}∖{1,3,4,5,8,10}={2,6}
• Elements in Y only (outside X and Z): Y∖(X∪Z)={1,3,4,5,8,10}∖({2,3,4,6}∪{1,3,5})={1,3,4,5,8,10}∖{1,2,3,4,5,6}={8,10}
• Elements in Z only: Z∖(X∪Y)=∅ (as Z⊂Y, and all elements are accounted for in X∩Y∩Z or (Y∩Z)∖X)
• Elements outside X∪Y∪Z: U∖(X∪Y∪Z)={1,...,10}∖({1,2,3,4,5,6,8,10})={7,9}
Step 3: Illustrate the information on a Venn diagram (part a).
A Venn diagram would show three overlapping circles for X, Y, and Z. The circle for Z would be drawn entirely inside the circle for Y. The elements are placed in the corresponding regions:
• The region common to X, Y, and Z (i.e., X∩Z): {3}
• The region common to X and Y but outside Z: {4}
• The region common to Y and Z but outside X: {1,5}
• The region for X only: {2,6}
• The region for Y only (outside X and Z): {8,10}
• The region outside all three sets: {7,9}
Step 4: Find X′∩Y (part b, i).
First, find the complement of X, denoted X′.
X′=U∖X={1,2,3,4,5,6,7,8,9,10}∖{2,3,4,6}={1,5,7,8,9,10}
Now, find the intersection of X′ and Y:
X′∩Y={1,5,7,8,9,10}∩{1,3,4,5,8,10}
X′∩Y={1,5,8,10}
Step 5: Find Z′∪(X∩Y) (part b, ii).
First, find the complement of Z, denoted Z′.
Z′=U∖Z={1,2,3,4,5,6,7,8,9,10}∖{1,3,5}={2,4,6,7,8,9,10}
Next, find the intersection of X and Y:
X∩Y={2,3,4,6}∩{1,3,4,5,8,10}={3,4}
Finally, find the union of Z′ and (X∩Y):
Z′∪(X∩Y)={2,4,6,7,8,9,10}∪{3,4}
Z′∪(X∩Y)={2,3,4,6,7,8,9,10}
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