If r = (3/4) and S = (1/2), Find r + s.

We are given the vectors:

$$r = \begin{pmatrix} 3 \\ 4 \end{pmatrix}$$ $$s = \begin{pmatrix} 1 \\ 2 \end{pmatrix}$$

To find $r+s$, we add the first components together and the second components together.

$$r+s = \begin{pmatrix} 3 \\ 4 \end{pmatrix} + \begin{pmatrix} 1 \\ 2 \end{pmatrix}$$ $$r+s = \begin{pmatrix} 3+1 \\ 4+2 \end{pmatrix}$$ $$r+s = \begin{pmatrix} 4 \\ 6 \end{pmatrix}$$

The sum of the vectors is:

$$\begin{pmatrix} 4 \\ 6 \end{pmatrix}$$