If the area of ╠TPL is 98m², find the area of the shaded.

The height of $\triangle TPL$ and $\triangle FTL$ is $h = 7 \text{ m}$.
The base of $\triangle TPL$ is $TP = (2x+4) \text{ m}$.
The area of $\triangle TPL$ is $98 \text{ m}^2$.
The base of the shaded region $\triangle FTL$ is $FT = 8 \text{ m}$.

The formula for the area of a triangle is $\frac{1}{2} \times \text{base} \times \text{height}$.

Substitute the given values:

Multiply both sides by 2:

Divide both sides by 7:

Subtract 4 from both sides:

Divide by 2:

The base of $\triangle FTL$ is $FT = 8 \text{ m}$.
The height of $\triangle FTL$ is $h = 7 \text{ m}$.

Substitute the values:

The area of the shaded region is $28 \text{ m}^2$.