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If ^x C2 = 4[^x Cx-1], find the values of x.

Mathematics

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9. (a) If xC2=4[xCx−1]^x C_2 = 4[^x C_{x-1}], find the values of xx.

Step 1: Use the combination formula nCr=n!r!(n−r)!^n C_r = \frac{n!}{r!(n-r)!} and the property nCr=nCn−r^n C_r = ^n C_{n-r}.
We are given xC2=4[xCx−1]^x C_2 = 4[^x C_{x-1}].
Using the property, xCx−1=xCx−(x−1)=xC1^x C_{x-1} = ^x C_{x-(x-1)} = ^x C_1.
So the equation becomes:

xC2=4(xC1)^x C_2 = 4(^x C_1)
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