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In a DEF, DE = 12 cm , DF = 9 cm, and EF = 10 cm. Calculate the following: a) DE² + DF² b) EF²

Mathematics

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Answers

2 parts
a

144 cm2144 \text{ cm}^2

b

144 cm2144 \text{ cm}^2

Step-by-step solution

3 steps

Here's the solution for :

Step 1: Identify the given side lengths of △DEF\triangle DEF.
DE=7.2 cmDE = 7.2 \text{ cm}
DF=9.6 cmDF = 9.6 \text{ cm}
EF=12 cmEF = 12 \text{ cm}

Part a· 2 steps

Calculate DE2+DF2DE^2 + DF^2

  1. Square the lengths of sides DE and DF.

    DE2=(7.2 cm)2=51.84 cm2DE^2 = (7.2 \text{ cm})^2 = 51.84 \text{ cm}^2 DF2=(9.6 cm)2=92.16 cm2DF^2 = (9.6 \text{ cm})^2 = 92.16 \text{ cm}^2
  2. Add the squared values.

    DE2+DF2=51.84 cm2+92.16 cm2=144 cm2DE^2 + DF^2 = 51.84 \text{ cm}^2 + 92.16 \text{ cm}^2 = 144 \text{ cm}^2

    The value of DE2+DF2DE^2 + DF^2 is 144 cm2\boxed{144 \text{ cm}^2}.

Part b

144 cm2144 \text{ cm}^2

Calculate EF2EF^2

  1. Square the length of side EF.

    EF2=(12 cm)2=144 cm2EF^2 = (12 \text{ cm})^2 = 144 \text{ cm}^2

    The value of EF2EF^2 is 144 cm2\boxed{144 \text{ cm}^2}.

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