In an Arithmetic progression the sun of three consecutive numbers is 93 find the numbers

Mathematics

ScanSolve AI Answer

Step-by-step solution

4 steps
  1. Represent the three consecutive numbers in an arithmetic progression.

    Let the three consecutive numbers be a−da-d, aa, and a+da+d, where aa is the middle term and dd is the common difference.

  2. Set up the equation based on the given sum.

    The sum of the three consecutive numbers is 93.

    (a−d)+a+(a+d)=93(a-d) + a + (a+d) = 93
  3. Solve for aa.

    Combine like terms:

    3a=933a = 93

    Divide by 3:

    a=933a = \frac{93}{3} a=31a = 31
  4. State the numbers.

    The middle

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