In circle ABCDE, AC is a chord. AFD EFB. If ADE = 40^ and AED = ABC, find AED.

Here's a step-by-step solution for Question 9.

Given Information:

• Circle ABCDE.
• AC is a chord.
• $AFD \perp EFB$, which means the lines $AD$ and $EB$ intersect at $F$ at a $90^\circ$ angle. So, $\angle AFE = \angle EFD = \angle DFB = \angle BFA = 90^\circ$.
• $\angle D1 = 40^\circ$, which is $\angle ADE = 40^\circ$.
• $\angle E = \angle B1$, which is $\angle AED = \angle ABC$.

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**9.1 Name THREE angles each equal to