In the sketch alongside, AB = AC and PQ = PR. Prove that racBDAC = racDRAQ.

Part (a):
In the sketch alongside, $AB = AC$ and $PQ = PR$. Prove that $\frac{BD}{AC} = \frac{DR}{AQ}$.

Step 1: Analyze the given information.
We are given that $AB = AC$. This means $\triangle ABC$ is an isosceles triangle, so $\angle ABC = \angle ACB$.
We are also given that $PQ = PR$. This means $\triangle PQR$ is an isosceles triangle, so $\angle PQR = \angle PRQ$.
From the diagram, $Q$ and $R$ lie on $BC$. Therefore, $\angle PQR = \angle PQB$ and $\angle PRQ =