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Evaluate the indefinite Integral: Integral(4x3 - 6x + 5)dx

Mathematics

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Answer

x4−3x2+5x+Cx^4 - 3x^2 + 5x + C

Step-by-step solution

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To evaluate the indefinite integral ∫(4x3−6x+5) dx\int (4x^3 - 6x + 5)\,dx, we will integrate each term separately using the power rule for integration, ∫xn dx=xn+1n+1+C\int x^n\,dx = \frac{x^{n+1}}{n+1} + C, and the constant rule, ∫k dx=kx+C\int k\,dx = kx + C.

  1. Integrate the first term, 4x34x^3.

    ∫4x3 dx=4∫x3 dx=4(x3+13+1)+C1=4(x44)+C1=x4+C1\int 4x^3\,dx = 4 \int x^3\,dx = 4 \left(\frac{x^{3+1}}{3+1}\right) + C_1 = 4 \left(\frac{x^4}{4}\right) + C_1 = x^4 + C_1
  2. Integrate the second term, −6x-6x.

    ∫−6x dx=−6∫x1 dx=−6(x1+11+1)+C2=−6(x22)+C2=−3x2+C2\int -6x\,dx = -6 \int x^1\,dx = -6 \left(\frac{x^{1+1}}{1+1}\right) + C_2 = -6 \left(\frac{x^2}{2}\right) + C_2 = -3x^2 + C_2
  3. Integrate the third term, 5.

    ∫5 dx=5x+C3\int 5\,dx = 5x + C_3
  4. Combine the results from each term and add a single constant of integration, CC, which represents the sum of C1,C2,C_1, C_2, and C3C_3.

    ∫(4x3−6x+5) dx=x4−3x2+5x+C\int (4x^3 - 6x + 5)\,dx = x^4 - 3x^2 + 5x + C

    The indefinite integral is:

    x4−3x2+5x+Cx^4 - 3x^2 + 5x + C
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