Solve the inequality: (2-x)/(x+1) >= 0

The expression is $\frac{2-x}{x+1} \ge 0$.
The numerator is zero when $2-x=0 \implies x=2$.
The denominator is zero when $x+1=0 \implies x=-1$.
These points divide the number line into three intervals: $(-\infty, -1)$, $(-1, 2)$, and $(2, \infty)$.

• For $x < -1$ (e.g., $x=-2$): $\frac{2-(-2)}{-2+1} = \frac{4}{-