Solve the inequality: (2-x)/(x+1) >= 0

April 13, 2026Mathematics

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April 13, 2026

Answer

0 \implies x=2$.

2. (ii) Step 1: Find the critical points of the inequality. The expression is $\frac{2-x}{x+1} \ge 0$ . The numerator is zero when $2-x=0 \implies x=2$ . The denominator is zero when $x+1=0 \implies x=-1$ . These points divide the number line into three intervals: $(-\infty, -1)$ , $(-1, 2)$ , and $(2, \infty)$ .

Step 2: Test a value in each interval to determine the sign of the expression. • For $x < -1$ (e.g., $x=-2$ ): $\frac{2-(-2)}{-2+1} = \frac{4}{-

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2. (ii) Step 1: Find the critical points of the inequality.

Asked on April 13, 2026Mathematics

This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.

ScanSolve AI AnswerAnswered on April 13, 2026

2. (ii) Step 1: Find the critical points of the inequality. The expression is (2-x)/(x+1) 0. The numerator is zero when 2-x=0 x=2. The denominator is zero when x+1=0 x=-1. These points divide the number line into three intervals: (-, -1), (-1, 2), and (2, ). Step 2: Test a value in each interval to determine the sign of the expression. • For x < -1 (e.g., x=-2): $(2-(-2))/(-2+1) = 4-