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Solve the integral: integral 5 x 4 x dx

Mathematics

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Answer

tan⁡6x6+tan⁡8x8+C\frac{\tan^6 x}{6} + \frac{\tan^8 x}{8} + C

Step-by-step solution

6 steps

To solve the integral ∫tan⁡5xsec⁡4x dx\int \tan^5 x \sec^4 x \, dx:

  1. Rewrite the integrand using trigonometric identities.

    We know that sec⁡2x=1+tan⁡2x\sec^2 x = 1 + \tan^2 x. We can split sec⁡4x\sec^4 x into sec⁡2x⋅sec⁡2x\sec^2 x \cdot \sec^2 x.

    ∫tan⁡5xsec⁡4x dx=∫tan⁡5xsec⁡2xsec⁡2x dx\int \tan^5 x \sec^4 x \, dx = \int \tan^5 x \sec^2 x \sec^2 x \, dx

    Substitute sec⁡2x=1+tan⁡2x\sec^2 x = 1 + \tan^2 x for one of the sec⁡2x\sec^2 x terms.

    ∫tan⁡5x(1+tan⁡2x)sec⁡2x dx\int \tan^5 x (1 + \tan^2 x) \sec^2 x \, dx
  2. Perform a substitution.

    Let u=tan⁡xu = \tan x.
    Then, the differential du=sec⁡2x dxdu = \sec^2 x \, dx.

  3. Substitute uu and dudu into the integral.

    ∫u5(1+u2) du\int u^5 (1 + u^2) \, du
  4. Expand the integrand.

    ∫(u5+u7) du\int (u^5 + u^7) \, du
  5. Integrate term by term using the power rule ∫xn dx=xn+1n+1+C\int x^n \, dx = \frac{x^{n+1}}{n+1} + C.

    u5+15+1+u7+17+1+C\frac{u^{5+1}}{5+1} + \frac{u^{7+1}}{7+1} + C u66+u88+C\frac{u^6}{6} + \frac{u^8}{8} + C
  6. Substitute back u=tan⁡xu = \tan x.

    tan⁡6x6+tan⁡8x8+C\frac{\tan^6 x}{6} + \frac{\tan^8 x}{8} + C
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