Step 1: Identify a suitable substitution.
Let u=x2+4x−7.
Step 2: Differentiate u with respect to x to find du.
dxdu=dxd(x2+4x−7)=2x+4
So, du=(2x+4)dx.
Step 3: Substitute u and du into the integral.
∫(x2+4x−7)(2x+4)dx=∫udu
Step 4: Integrate with respect to u.
∫udu=1+1u1+1+C=2u2+C
Step 5: Substitute back u=x2+4x−7 into the result.
2(x2+4x−7)2+C
The final answer is 2(x2+4x−7)2+C.
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