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Integrate (6x2 - x + 3) dx

Mathematics

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Answer

2x3−x22+3x+C2x^3 - \frac{x^2}{2} + 3x + C

Step-by-step solution

4 steps
  1. Apply the linearity property of integration, which states that the integral of a sum or difference is the sum or difference of the integrals, and constants can be pulled out of the integral.

    ∫(6x2−x+3) dx=∫6x2 dx−∫x dx+∫3 dx\int (6x^2 - x + 3)\,dx = \int 6x^2\,dx - \int x\,dx + \int 3\,dx
  2. Apply the power rule for integration, which is ∫xn dx=xn+1n+1+C\int x^n\,dx = \frac{x^{n+1}}{n+1} + C (for n≠−1n \neq -1), to each term.

    For the first term, 6x26x^2:

    ∫6x2 dx=6⋅x2+12+1=6⋅x33\int 6x^2\,dx = 6 \cdot \frac{x^{2+1}}{2+1} = 6 \cdot \frac{x^3}{3}

    For the second term, −x-x (which is −x1-x^1):

    ∫−x dx=−x1+11+1=−x22\int -x\,dx = - \frac{x^{1+1}}{1+1} = - \frac{x^2}{2}

    For the third term, 3 (which is 3x03x^0):

    ∫3 dx=3⋅x0+10+1=3⋅x11=3x\int 3\,dx = 3 \cdot \frac{x^{0+1}}{0+1} = 3 \cdot \frac{x^1}{1} = 3x
  3. Combine the results from each term and add the constant of integration, CC.

    6⋅x33−x22+3x+C6 \cdot \frac{x^3}{3} - \frac{x^2}{2} + 3x + C
  4. Simplify the expression.

    2x3−x22+3x+C2x^3 - \frac{x^2}{2} + 3x + C
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