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Integrate integral x dx

Mathematics

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Answer

15sin⁡(5x)+C\frac{1}{5} \sin(5x) + C

Step-by-step solution

5 steps

Okay, m. Let's integrate this.

  1. Identify the integral.

    The problem asks to integrate cos⁡(5x)\cos(5x).

    ∫cos⁡(5x) dx\int \cos(5x) \, dx
  2. Use a substitution.

    Let u=5xu = 5x.
    Then, differentiate uu with respect to xx:

    dudx=5\frac{du}{dx} = 5

    Rearrange to find dxdx:

    dx=15 dudx = \frac{1}{5} \, du
  3. Substitute uu and dxdx into the integral.

    ∫cos⁡(u)(15) du\int \cos(u) \left( \frac{1}{5} \right) \, du =15∫cos⁡(u) du= \frac{1}{5} \int \cos(u) \, du
  4. Integrate with respect to uu.

    The integral of cos⁡(u)\cos(u) is sin⁡(u)\sin(u).

    =15sin⁡(u)+C= \frac{1}{5} \sin(u) + C
  5. Substitute back u=5xu = 5x.

    =15sin⁡(5x)+C= \frac{1}{5} \sin(5x) + C

    The final answer is 15sin⁡(5x)+C\frac{1}{5} \sin(5x) + C.

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