A ship sails 300 km due west and then 100 km due south. At the end of this journey, how far is the ship from its starting position?
|Mathematics
A ship sails 300 km due west and then 100 km due south. At the end of this journey, how far is the ship from its starting position?
ScanSolve AI Answer
Answer
10010km
Step 1: The journey forms a right triangle with legs of 300 km (west) and 100 km (south).
The straight-line distance d from start to end is the hypotenuse: d=(300km)2+(100km)2
Step 2: Square the distances. (300)2=90,000 (100)2=10,000
Step 3: Add the squares. 90,000+10,000=100,000
Step 4: Take the square root. d=100,000=10,000×10=10010km
Final answer: 10010km
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This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.
ScanSolve AI Answer
Step 1: The journey forms a right triangle with legs of 300 km (west) and 100 km (south). The straight-line distance d from start to end is the hypotenuse: d = sqrt((300~km))^2 + (100~km)^2 Step 2: Square the distances. (300)^2 = 90,000 (100)^2 = 10,000 Step 3: Add the squares. 90,000 + 10,000 = 100,000 Step 4: Take the square root. d = sqrt(100,)000 = sqrt(10,)000 × 10 = 100sqrt(10)~km Final answer: 100sqrt(10)~km