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Find the lettered angles in each of the following.

Mathematics

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Here are the solutions for the lettered angles in each figure.

Figure 1 (Fig. 9.19)

The arrows on the lines indicate that they are parallel. We will use the properties of angles formed by parallel lines and transversals.

  1. Identify the interior angle at the bottom vertex.

    The angle 340∘340^\circ is a reflex angle. The interior angle at that vertex is the difference between 360∘360^\circ and the reflex angle.

    Interior angle=360∘−340∘=20∘\text{Interior angle} = 360^\circ - 340^\circ = 20^\circ
  2. Apply the "M-rule" (also known as the "zigzag rule").

    Draw an auxiliary line through the vertex where angles ff and 80∘80^\circ are located, parallel to the two main parallel lines. This line divides the angle at that vertex into two parts.
    The "M-rule" states that the sum of angles pointing in one direction (e.g., left) equals the sum of angles pointing in the opposite direction (e.g., right).
    In this figure, the angles ee and ff point to the left, and the angles 80∘80^\circ and 20∘20^\circ (the interior angle at the bottom) point to the right.
    Therefore, we have:

    e+f=80∘+20∘e + f = 80^\circ + 20^\circ e+f=100∘e + f = 100^\circ

    This equation has two unknowns. Let's re-examine the diagram for a clearer interpretation of ff and 80∘80^\circ.

    Upon closer inspection, the angle 80∘80^\circ is shown adjacent to ff at the same vertex, and both are inside the "V" shape. This is an unusual way to label. The most common interpretation for such a diagram is that the angle formed by the two transversals at the middle vertex is the sum of ff and 80∘80^\circ. So, the angle at the middle vertex is (f+80∘)(f+80^\circ).

    Let's re-apply the "M-rule" with this interpretation:
    Angles pointing left: ee and the interior angle at the bottom (20∘20^\circ).
    Angles pointing right: The angle at the middle vertex, which is (f+80∘)(f+80^\circ).

    e+20∘=f+80∘e + 20^\circ = f + 80^\circ e−f=80∘−20∘e - f = 80^\circ - 20^\circ e−f=60∘e - f = 60^\circ

    This still leaves two unknowns.

    Let's consider another common interpretation for such diagrams: the 80∘80^\circ is an angle between the top transversal and the middle transversal, and ff is an angle between the middle transversal and the bottom transversal. In this case, the 80∘80^\circ and ff are separate angles at different "bends" of the zigzag. However, the diagram clearly shows ff and 80∘80^\circ at the same vertex.

    Given the way ff and 80∘80^\circ are drawn at the same vertex, with ff having a circle around it (often indicating the angle itself) and 80∘80^\circ also marked inside, it implies that the angle ff is 80∘80^\circ. This is the only way to get a unique solution for ee.

  3. Assume f=80∘f = 80^\circ based on the diagram's labeling at the middle vertex.

    If f=80∘f = 80^\circ, then using the "M-rule" where angles pointing left (ee and 20∘20^\circ) equal angles pointing right (ff):

    e+20∘=fe + 20^\circ = f

    Substitute f=80∘f = 80^\circ:

    e+20∘=80∘e + 20^\circ = 80^\circ e=80∘−20∘e = 80^\circ - 20^\circ e=60∘e = 60^\circ

    Let's verify this with the auxiliary line method.
    Draw an auxiliary line through the vertex of ff parallel to the main parallel lines. This line divides ff into two parts, f1f_1 (top part) and f2f_2 (bottom part).
    f1f_1 is alternate interior to ee. So f1=e=60∘f_1 = e = 60^\circ.
    f2f_2 is alternate interior to the 20∘20^\circ angle at the bottom. So f2=20∘f_2 = 20^\circ.
    Then f=f1+f2=60∘+20∘=80∘f = f_1 + f_2 = 60^\circ + 20^\circ = 80^\circ.
    This is consistent with our assumption that f=80∘f=80^\circ.

    Therefore, for Fig. 9.19:

    • e=60∘e = \mathbf{60^\circ}
    • f=80∘f = \mathbf{80^\circ}

    Figure 2 (Fig. 9.20)

    The arrows on the lines indicate that they are parallel.

  4. Identify the angles pointing left and right.

    Draw an auxiliary line through the vertex where angles gg and hh are located, parallel to the two main parallel lines. This line divides the angle at that vertex into two parts.
    The "M-rule" states that the sum of angles pointing in one direction (e.g., left) equals the sum of angles pointing in the opposite direction (e.g., right).
    In this figure, the angles 58∘58^\circ and 42∘42^\circ point to the left.
    The angle at the middle vertex, which is (g+h)(g+h), points to the right.
    Therefore, we have:

    58∘+42∘=g+h58^\circ + 42^\circ = g + h 100∘=g+h100^\circ = g + h
  5. Determine the individual values of gg and hh.

    The circle around hh indicates that hh is the angle inside the "V" shape at that vertex. The angle gg is shown adjacent to hh, also inside the "V" shape. This implies that the total angle at that vertex is g+hg+h.
    However, the diagram also shows gg as a separate angle. In such diagrams, if two letters are at the same vertex, they usually represent parts of the total angle.
    Let's assume gg and hh are the two parts of the angle at the middle vertex.
    The angle gg is alternate interior to the 58∘58^\circ angle.
    The angle hh is alternate interior to the 42∘42^\circ angle.

  6. Calculate gg.

    Draw an auxiliary line through the vertex of gg and hh, parallel to the top and bottom parallel lines.
    The angle gg and the angle 58∘58^\circ are alternate interior angles.

    g=58∘g = 58^\circ
  7. Calculate hh.

    The angle hh and the angle 42∘42^\circ are alternate interior angles.

    h=42∘h = 42^\circ
  8. Verify the sum.

    g+h=58∘+42∘=100∘g + h = 58^\circ + 42^\circ = 100^\circ

    This matches the sum derived from the "M-rule" in Step 1.

    Therefore, for Fig. 9.20:

    • g=58∘g = \mathbf{58^\circ}
    • h=42∘h = \mathbf{42^\circ}

    Final Answers:
    For Fig. 9.19:

    • e=60∘e = \boxed{\mathbf{60^\circ}}
    • f=80∘f = \boxed{\mathbf{80^\circ}}

    For Fig. 9.20:

    • g=58∘g = \boxed{\mathbf{58^\circ}}
    • h=42∘h = \boxed{\mathbf{42^\circ}}
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