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Evaluate the limit: _x infinity (1 - (2)/(x))^x

Mathematics

ScanSolve AI Answer

Answer

1e2\frac{1}{e^2}

Step-by-step solution

5 steps

Let's find the limit of the given function.

The problem asks to evaluate the limit:

lim⁡x→∞(1−2x)x\lim_{x \to \infty} \left(1 - \frac{2}{x}\right)^x
  1. Recognize the form of the limit.

    This limit is in the indeterminate form 1∞1^\infty as x→∞x \to \infty, since (1−2x)→(1−0)=1\left(1 - \frac{2}{x}\right) \to (1 - 0) = 1. This form is related to the definition of the mathematical constant ee.

  2. Apply the standard limit formula for ee.

    A common limit definition for ee is:

    lim⁡x→∞(1+kx)x=ek\lim_{x \to \infty} \left(1 + \frac{k}{x}\right)^x = e^k

    where kk is a constant.

  3. Compare the given limit with the standard formula.

    In our problem, we have (1−2x)x\left(1 - \frac{2}{x}\right)^x. We can rewrite this as (1+−2x)x\left(1 + \frac{-2}{x}\right)^x.
    By comparing this to the standard formula, we can identify k=−2k = -2.

  4. Substitute the value of kk into the formula.

    Using k=−2k = -2:

    lim⁡x→∞(1+−2x)x=e−2\lim_{x \to \infty} \left(1 + \frac{-2}{x}\right)^x = e^{-2}
  5. Express the result with a positive exponent.

    e−2=1e2e^{-2} = \frac{1}{e^2}

    The final answer is:

    1e2\frac{1}{e^2}
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