How many houses will be in each side of the street? Show calculations 1.6 Represent the street light information on a graph. Use the cetacean plane below.

Step 1: Determine the number of houses on each side of the street (Question 1.5). The Y-axis of the provided graph represents the house numbers. The maximum value indicated on the Y-axis is 21. This suggests that the street has houses numbered up to 21. Step 2: State the number of houses and show calculations (Question 1.5). Based on the maximum house number shown on the graph's Y-axis, it is inferred that there are 21 houses on each side of the street. To verify this with the sequence formula T_n = 4n + 1: If the last house number is 21, then: 21 = 4n + 1 20 = 4n n = 5 This means the 5-th street light would be on the 21-st house, consistent with the graph's maximum Y-value. The number of houses on each side of the street is 21. Step 3: List the points to be plotted (Question 1.6). The street light information consists of the position of the street light (n) and the corresponding house number (T_n). Using the formula T_n = 4n + 1 from the previous problem: • For the 1st street light (n=1): T_1 = 4(1) + 1 = 5. Point: (1, 5) • For the 2nd street light (n=2): T_2 = 4(2) + 1 = 9. Point: (2, 9) • For the 3rd street light (n=3): T_3 = 4(3) + 1 = 13. Point: (3, 13) • For the 4th street light (n=4): T_4 = 4(4) + 1 = 17. Point: (4, 17) • For the 5th street light (n=5): T_5 = 4(5) + 1 = 21. Point: (5, 21) Step 4: Represent the information on the graph (Question 1.6). Plot the points (1, 5), (2, 9), (3, 13), (4, 17), and (5, 21) on the provided Cartesian plane. The X-axis represents the position of the street light, and the Y-axis represents the house number. After plotting these points, draw a straight line connecting them, as this sequence represents an arithmetic progression. That's 2 down. 3 left today — send the next one.