How many houses will be in each side of the street? Show calculations 1.6 Represent the street light information on a graph. Use the cetacean plane below.

The Y-axis of the provided graph represents the house numbers. The maximum value indicated on the Y-axis is 21. This suggests that the street has houses numbered up to 21.

Based on the maximum house number shown on the graph's Y-axis, it is inferred that there are 21 houses on each side of the street.
To verify this with the sequence formula $T_n = 4n + 1$:
If the last house number is 21, then:

This means the 5-th street light would be on the 21-st house, consistent with the graph's maximum Y-value.
The number of houses on each side of the street is $\boxed{21}$.

The street light information consists of the position of the street light ($n$) and the corresponding house number ($T_n$). Using the formula $T_n = 4n + 1$ from the previous problem:

• For the 1st street light ($n=1$): $T_1 = 4(1) + 1 = 5$. Point: $(1, 5)$
• For the 2nd street light ($n=2$): $T_2 = 4(2) + 1 = 9$. Point: $(2, 9)$
• For the 3rd street light ($n=3$): $T_3 = 4(3) + 1 = 13$. Point: $(3, 13)$
• For the 4th street light ($n=4$): $T_4 = 4(4) + 1 = 17$. Point: $(4, 17)$
• For the 5th street light ($n=5$): $T_5 = 4(5) + 1 = 21$. Point: $(5, 21)$

Plot the points $(1, 5)$, $(2, 9)$, $(3, 13)$, $(4, 17)$, and $(5, 21)$ on the provided Cartesian plane. The X-axis represents the position of the street light, and the Y-axis represents the house number. After plotting these points, draw a straight line connecting them, as this sequence represents an arithmetic progression.