एक गैसीय हाइड्रोकार्बन, दहन पर 0.72 g जल और 3.08 g CO2 देता है। हाइड्रोकार्बन का मूलानुपाती सूत्र है -

Chemistry
एक गैसीय हाइड्रोकार्बन, दहन पर 0.72 g जल और 3.08 g CO2 देता है। हाइड्रोकार्बन का मूलानुपाती सूत्र है -

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Answer

92 g/mol

Step 1: Calculate mass of carbon from CO₂.

MassofC=1244×3.08 gMass of C = \frac{12}{44} \times 3.08~g 1244=311\frac{12}{44} = \frac{3}{11} 3×3.0811=9.2411=0.84 g\frac{3 \times 3.08}{11} = \frac{9.24}{11} = 0.84~g

Step 2: Calculate mass of hydrogen from H₂O.

MassofH=218×0.72 gMass of H = \frac{2}{18} \times 0.72~g 218=19\frac{2}{18} = \frac{1}{9} 0.729=0.08 g\frac{0.72}{9} = 0.08~g

Step 3: Calculate mass of hydrocarbon.

Massofhydrocarbon=0.84 g+0.08 g=0.92 gMass of hydrocarbon = 0.84~g + 0.08~g = 0.92~g

Step 4: Calculate moles of C and H atoms.

MolesofC=0.8412=0.07 molMoles of C = \frac{0.84}{12} = 0.07~mol MolesofH=0.081=0.08 molMoles of H = \frac{0.08}{1} = 0.08~mol

Step 5: Find simplest ratio of C:H atoms.

C:H=0.07:0.08=7:8C:H = 0.07 : 0.08 = 7 : 8

Empirical formula is \ceC7H8\ce{C7H8}.

Step 6: Calculate molar mass of \ceC7H8\ce{C7H8}.

M=(7×12)+(8×1)=84+8=92 g/molM = (7 \times 12) + (8 \times 1) = 84 + 8 = 92~g/mol

Final answer: 9292 g/mol
92 g/mol

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Quick Answer

Calculate mass of carbon from CO₂. Mass of C = (12)/(44) × 3.08~g (12)/(44) = (3)/(11) (3 × 3.08)/(11) = (9.24)/(11) = 0.84~g Step 2: Calculate mass of hydrogen from H₂O.

एक गैसीय हाइड्रोकार्बन, दहन पर 0.72 g जल और 3.08 g CO2 देता है। हाइड्रोकार्बन का मूलानुपाती सूत्र है -
Chemistry

This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.

ScanSolve AI Answer
Step 1: Calculate mass of carbon from CO₂. Mass of C = (12)/(44) × 3.08~g (12)/(44) = (3)/(11) (3 × 3.08)/(11) = (9.24)/(11) = 0.84~g Step 2: Calculate mass of hydrogen from H₂O. Mass of H = (2)/(18) × 0.72~g (2)/(18) = (1)/(9) (0.72)/(9) = 0.08~g Step 3: Calculate mass of hydrocarbon. Mass of hydrocarbon = 0.84~g + 0.08~g = 0.92~g Step 4: Calculate moles of C and H atoms. Moles of C = (0.84)/(12) = 0.07~mol Moles of H = (0.08)/(1) = 0.08~mol Step 5: Find simplest ratio of C:H atoms. C:H = 0.07 : 0.08 = 7 : 8 Empirical formula is C7H8. Step 6: Calculate molar mass of C7H8. M = (7 × 12) + (8 × 1) = 84 + 8 = 92~g/mol Final answer: 92 g/mol 92 g/mol