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15 cm³ of ethanoic acid was dissolved in water to make 500cm³ of solution. Calculate the concentration of the solution in moles per litre (C=12, H=1, O=16, density of ethanoic acid is 1.05g/cm³)

March 16, 2026Chemistry

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Answer

0.70 M

4 steps

Calculate the mass of ethanol acid.
Formula:
$\text{mass} = V \times \rho$
Substitute:
$\text{mass} = 20 \, \mathrm{mL} \times 1.05 \, \frac{\mathrm{g}}{\mathrm{mL}} = 21 \, \mathrm{g}$
Calculate the number of moles of ethanol acid.
Formula:
$n = \frac{\text{mass}}{M_r}$
Substitute:
$n = \frac{21 \, \mathrm{g}}{60 \, \frac{\mathrm{g}}{\mathrm{mol}}} = 0.35 \, \mathrm{mol}$
Convert the volume of solution to liters.
$V = 500 \, \mathrm{mL} = 0.500 \, \mathrm{L}$
Calculate the concentration of the solution.
Formula:
$c = \frac{n}{V}$
Substitute:
$c = \frac{0.35 \, \mathrm{mol}}{0.500 \, \mathrm{L}} = 0.70 \, \frac{\mathrm{mol}}{\mathrm{L}}$
0.70 M

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