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Calculate the mean of the frequency distribution shown in the table and histogram.

Mathematics

ScanSolve AI Answer

Answer

62.72\text{62.72}

Step-by-step solution

4 steps

The image displays a frequency distribution table and a histogram. Since no specific question was asked, I will calculate the mean of the distribution, which is a common task for such data.

  1. Identify the class centers (xx) and frequencies (ff) from the table.

    The class centers are already provided in the table.

    Class limitsFrequency (ff)Class center (xx)
    40−4940 - 491344.5
    50−5950 - 59954.5
    60−6960 - 69664.5
    70−7970 - 79874.5
    80−8980 - 89884.5
    90−9990 - 99194.5
  2. Calculate the product of frequency and class center (f⋅xf \cdot x) for each class.

    For 40−4940 - 49: 13×44.5=578.513 \times 44.5 = 578.5
    For 50−5950 - 59: 9×54.5=490.59 \times 54.5 = 490.5
    For 60−6960 - 69: 6×64.5=387.06 \times 64.5 = 387.0
    For 70−7970 - 79: 8×74.5=596.08 \times 74.5 = 596.0
    For 80−8980 - 89: 8×84.5=676.08 \times 84.5 = 676.0
    For 90−9990 - 99: 1×94.5=94.51 \times 94.5 = 94.5

  3. Calculate the sum of frequencies (∑f\sum f) and the sum of the products (∑(f⋅x)\sum (f \cdot x)).

    ∑f=13+9+6+8+8+1=45\sum f = 13 + 9 + 6 + 8 + 8 + 1 = 45 ∑(f⋅x)=578.5+490.5+387.0+596.0+676.0+94.5=2822.5\sum (f \cdot x) = 578.5 + 490.5 + 387.0 + 596.0 + 676.0 + 94.5 = 2822.5
  4. Calculate the mean (xˉ\bar{x}) using the formula xˉ=∑(f⋅x)∑f\bar{x} = \frac{\sum (f \cdot x)}{\sum f}.

    xˉ=2822.545\bar{x} = \frac{2822.5}{45} xˉ≈62.7222...\bar{x} \approx 62.7222...

    Rounding to two decimal places:

    xˉ≈62.72\bar{x} \approx 62.72

    The mean of the distribution is 62.72\text{62.72}.

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