This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.
ScanSolve AI Answer
Step 1: Molar mass of BaSO4 M(BaSO4) = 137 + 32 + 64 = 233~g/mol Step 2: Mass of sulfur in 1.02~g of BaSO4 Formula: mass~of~S = (32)/(233) × mass~of~BaSO4 Substitute: mass~of~S = (32)/(233) × 1.02~g Calculate (32)/(233): (32)/(233) ≈ 0.13734 Then: 0.13734 × 1.02 = 0.1401~g Step 3: Percentage of sulfur in the compound Formula: \%S = ( mass~of~Smass~of~compound ) × 100 Substitute: \%S = ( 0.1401~g2.18~g ) × 100 Simplify: (0.1401)/(2.18) ≈ 0.06427 0.06427 × 100 = 6.43\% ≈ 6.42\% Answer: (d) 6.42\% 6.42\%