This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.
ScanSolve AI Answer
1(a) Molar mass of Na_2CO_3: 2×23 + 12 + 3×16 = 46 + 12 + 48 = 106\,g/mol Step 1: Mass = n × M = 0.4\,mol × 106\,g/mol = 42.4\,g 42.4 g 1(b) Step 1: c = (n)/(V) V = (n)/(c) = 0.4\,mol0.3\,mol/L = 1.33\,L 1.33 L 2(a) Step 1: n = c × V = 0.2\,mol/L × 0.5\,L = 0.1\,mol Step 2: Mass = n × M = 0.1\,mol × 106\,g/mol = 10.6\,g 10.6 g 2(b) Current: 0.5\,L of 0.2\,M, n=0.1\,mol Step 1: New c=0.1\,M V' = (n)/(c') = 0.1\,mol0.1\,mol/L = 1\,L Step 2: Water added = V' - V = 1\,L - 0.5\,L = 0.5\,L = 500\,mL 500 mL 3 Moles AgNO_3: n_Ag^+ = 0.1\,mol/L × 0.025\,L = 0.0025\,mol Moles NaCl: n_Cl^- = 0.2\,mol/L × 0.020\,L = 0.004\,mol NaCl solution is in excess (more Cl^-). Step 1: Excess Cl^- = 0.004\,mol - 0.0025\,mol = 0.0015\,mol NaCl solution; 0.0015 mol 4 |c|c|c| Type of cell & Coordination number & Number of particles per cell \\ Simple cubic & 6 & 1 \\ Face-centered cubic & 12 & 4 \\ Body-centered cubic & 8 & 2 \\ (d) Body-centered cubic structure is used to calculate lattice energy for metals like Fe, Cr, etc. (e) Lattice energy is the energy released when one mole of an ionic compound in gaseous state forms a solid crystal lattice. Lattice energy: energy released on forming 1 mol ionic solid from gaseous ions