Step 1: Identify the given values.
The principal amount borrowed is P=N8000.
The annual interest rate is r=7%=0.07.
The loan term is T=2 years.
The payments are made monthly.
Step 2: Calculate the monthly interest rate and the total number of payments.
The monthly interest rate i is the annual rate divided by 12:
i=120.07
The total number of payments n is the loan term in years multiplied by 12:
n=2years×12months/year=24 months
Step 3: Use the loan payment formula for an amortizing loan.
The formula for the monthly payment M is:
M=P(1+i)n−1i(1+i)n
Substitute the values:
M=8000(1+120.07)24−1120.07(1+120.07)24
Calculate the value of 1+120.07:
1+120.07≈1+0.005833333=1.005833333
Calculate (1+120.07)24:
(1.005833333)24≈1.149716
Now substitute these values back into the formula for M:
M=80001.149716−10.005833333×1.149716
M=80000.1497160.006706676
M=8000×0.044795
M≈358.36
The monthly payment is approximately N358.36.
The monthly payment is N358.36.
a) Evaluate 41A−2B.
Step 1: Calculate 41A.
41A=41(40−13)=(41×441×041×(−1)41×3)=(10−4143)
Step 2: Calculate 2B.
2B=2(−2110)=(2×(−2)2×12×12×0)=(−4220)
Step 3: Subtract 2B from 41A.
41A−2B=(10−4143)−(−4220)
=(1−(−4)0−2−41−243−0)
=(1+4−2−41−4843)
=(5−2−4943)
The result is (5−2−4943).
b) Evaluate B+3A.
Step 1: Calculate 3A.
3A=3(40−13)=(3×43×03×(−1)3×3)=(120−39)
Step 2: Add B to 3A.
B+3A=(−2110)+(120−39)
=(−2+121+01+(−3)0+9)
=(101−29)
The result is (101−29).
Step 1: Apply the logarithm property logbM−logbN=logb(NM).
The given equation is:
log3(x2)−log3x=2
Applying the property:
log3(xx2)=2
Step 2: Simplify the expression inside the logarithm.
log3x=2
Step 3: Convert the logarithmic equation to an exponential equation.
If logbY=X, then bX=Y.
Here, b=3, Y=x, and X=2.
x=32
Step 4: Calculate the value of x.
x=9
For the logarithms to be defined, x2>0 and x>0. Our solution x=9 satisfies these conditions.
The value of x is 9.
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