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Find the nature of roots for quadratic equations and calculate if alpha and beta are the roots of the equation 3x2 − 5x + 4 = 0, find the value of alpha/beta + beta/alpha.

Mathematics

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Step-by-step solution

15 steps

1) Find the nature of roots for the following quadratic equations

Part a· 3 steps

2x2−5x+2=02x^2 - 5x + 2 = 0

  1. Identify $a, b, c$.

    a=2a = 2, b=−5b = -5, c=2c = 2.

  2. Calculate the discriminant Δ=b2−4ac\Delta = b^2 - 4ac.

    Δ=(−5)2−4(2)(2)=25−16=9\Delta = (-5)^2 - 4(2)(2) = 25 - 16 = 9
  3. Determine the nature of roots.

    Since Δ=9>0\Delta = 9 > 0, the roots are real and distinct.
    The roots are real and distinct\boxed{\text{real and distinct}}.

Part b· 12 steps

3x2−7x+4=03x^2 - 7x + 4 = 0

  1. Identify $a, b, c$.

    a=3a = 3, b=−7b = -7, c=4c = 4.

  2. Calculate the discriminant Δ=b2−4ac\Delta = b^2 - 4ac.

    Δ=(−7)2−4(3)(4)=49−48=1\Delta = (-7)^2 - 4(3)(4) = 49 - 48 = 1
  3. Determine the nature of roots.

    Since Δ=1>0\Delta = 1 > 0, the roots are real and distinct.
    The roots are real and distinct\boxed{\text{real and distinct}}.

    2) If α\alpha and β\beta are the roots of the equation 3x2−5x+4=03x^2 - 5x + 4 = 0, find the value of α/β+β/α\alpha/\beta + \beta/\alpha.

  4. Identify $a, b, c$ and find the sum and product of roots.

    For 3x2−5x+4=03x^2 - 5x + 4 = 0, a=3a = 3, b=−5b = -5, c=4c = 4.
    Sum of roots: α+β=−ba=−−53=53\alpha + \beta = -\frac{b}{a} = -\frac{-5}{3} = \frac{5}{3}.
    Product of roots: αβ=ca=43\alpha\beta = \frac{c}{a} = \frac{4}{3}.

  5. Simplify the expression αβ+βα\frac{\alpha}{\beta} + \frac{\beta}{\alpha}.

    αβ+βα=α2+β2αβ\frac{\alpha}{\beta} + \frac{\beta}{\alpha} = \frac{\alpha^2 + \beta^2}{\alpha\beta}
  6. Use the identity α2+β2=(α+β)2−2αβ\alpha^2 + \beta^2 = (\alpha + \beta)^2 - 2\alpha\beta.

    α2+β2=(53)2−2(43)=259−83=259−249=19\alpha^2 + \beta^2 = \left(\frac{5}{3}\right)^2 - 2\left(\frac{4}{3}\right) = \frac{25}{9} - \frac{8}{3} = \frac{25}{9} - \frac{24}{9} = \frac{1}{9}
  7. Substitute the values into the simplified expression.

    α2+β2αβ=1943=19×34=336=112\frac{\alpha^2 + \beta^2}{\alpha\beta} = \frac{\frac{1}{9}}{\frac{4}{3}} = \frac{1}{9} \times \frac{3}{4} = \frac{3}{36} = \frac{1}{12}

    The value is 112\boxed{\frac{1}{12}}.

    3) If α\alpha and β\beta are the root of the equation 2x2−4x+7=02x^2 - 4x + 7 = 0, find α2+β2\alpha^2 + \beta^2.

  8. Identify $a, b, c$ and find the sum and product of roots.

    For 2x2−4x+7=02x^2 - 4x + 7 = 0, a=2a = 2, b=−4b = -4, c=7c = 7.
    Sum of roots: α+β=−ba=−−42=2\alpha + \beta = -\frac{b}{a} = -\frac{-4}{2} = 2.
    Product of roots: αβ=ca=72\alpha\beta = \frac{c}{a} = \frac{7}{2}.

  9. Use the identity α2+β2=(α+β)2−2αβ\alpha^2 + \beta^2 = (\alpha + \beta)^2 - 2\alpha\beta.

    α2+β2=(2)2−2(72)=4−7=−3\alpha^2 + \beta^2 = (2)^2 - 2\left(\frac{7}{2}\right) = 4 - 7 = -3

    The value is −3\boxed{-3}.

    4) Construct and simplify equations whose roots are −3,1-3, 1.

  10. Find the sum of the roots.

    Sum of roots =−3+1=−2= -3 + 1 = -2.

  11. Find the product of the roots.

    Product of roots =(−3)(1)=−3= (-3)(1) = -3.

  12. Construct the quadratic equation using the form x2−(sum of roots)x+(product of roots)=0x^2 - (\text{sum of roots})x + (\text{product of roots}) = 0.

    x2−(−2)x+(−3)=0x^2 - (-2)x + (-3) = 0 x2+2x−3=0x^2 + 2x - 3 = 0

    The equation is x2+2x−3=0\boxed{x^2 + 2x - 3 = 0}.

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