Please don't be rude I'm just a student who wants to know more about inequality I was asking for examples of problems to solve and teach me

Mathematics

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Answer

x<8x < 8

x≤−4x \le -4

x≤−6x \le -6

Step-by-step solution

7 steps

I apologize if my previous responses came across as too direct. I'm here to help you learn! Let's work through some examples to understand how to solve inequalities.

Example 1: Basic Linear Inequality

Solve for xx:

2x−5<112x - 5 < 11
  1. Add 5 to both sides of the inequality.

    This uses the Addition Property of inequalities.

    2x−5+5<11+52x - 5 + 5 < 11 + 5 2x<162x < 16
  2. Divide both sides by 2.

    Since 2 is a positive number, the direction of the inequality remains the same. This uses the Multiplication/Division Property.

    2x2<162\frac{2x}{2} < \frac{16}{2} x<8x < 8

    The solution is all real numbers less than 8.

    x<8\boxed{x < 8}

    Example 2: Inequality with Multiplication/Division by a Negative Number

    Solve for xx:

    −3x+7≥19-3x + 7 \ge 19
  3. Subtract 7 from both sides of the inequality.

    −3x+7−7≥19−7-3x + 7 - 7 \ge 19 - 7 −3x≥12-3x \ge 12
  4. Divide both sides by -3.

    Since -3 is a negative number, we must reverse the direction of the inequality sign.

    −3x−3≤12−3\frac{-3x}{-3} \le \frac{12}{-3} x≤−4x \le -4

    The solution is all real numbers less than or equal to -4.

    x≤−4\boxed{x \le -4}

    Example 3: Inequality with Variables on Both Sides

    Solve for xx:

    4x+3≤2x−94x + 3 \le 2x - 9
  5. Subtract 2x2x from both sides to gather the xx terms on one side.

    4x+3−2x≤2x−9−2x4x + 3 - 2x \le 2x - 9 - 2x 2x+3≤−92x + 3 \le -9
  6. Subtract 3 from both sides to isolate the xx term.

    2x+3−3≤−9−32x + 3 - 3 \le -9 - 3 2x≤−122x \le -12
  7. Divide both sides by 2.

    Since 2 is a positive number, the inequality direction remains the same.

    2x2≤−122\frac{2x}{2} \le \frac{-12}{2} x≤−6x \le -6

    The solution is all real numbers less than or equal to -6.

    x≤−6\boxed{x \le -6}
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