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Determine the period and phase angle for the function y = 6sin(x/2 - 90°).

Mathematics

ScanSolve AI Answer

Answer

720∘\text{720}^\circ

180∘\text{180}^\circ

Step-by-step solution

4 steps

Ili kubaini kipindi na pembe ya awamu ya kazi ya trigonometric y=Asin⁡(Bx−C)+Dy = A\sin(Bx - C) + D, tunatumia fomula zifuatazo:

  • Kipindi (Period) =360∘∣B∣= \frac{360^\circ}{|B|}
  • Pembe ya Awamu (Phase Angle) =CB= \frac{C}{B}

Kazi uliyopewa ni y=6sin⁡(x2−90∘)y = 6\sin\left(\frac{x}{2} - 90^\circ\right).
Kwa kulinganisha na fomu ya jumla, tunaona:
A=6A = 6
B=12B = \frac{1}{2}
C=90∘C = 90^\circ

  1. Bainisha thamani ya BB.

    Kutoka kwa kazi, B=12B = \frac{1}{2}.

  2. Kokotoa kipindi.

    Kipindi=360∘∣B∣=360∘∣12∣=360∘12=360∘×2=720∘\text{Kipindi} = \frac{360^\circ}{|B|} = \frac{360^\circ}{\left|\frac{1}{2}\right|} = \frac{360^\circ}{\frac{1}{2}} = 360^\circ \times 2 = 720^\circ
  3. Bainisha thamani ya CC.

    Kutoka kwa kazi, C=90∘C = 90^\circ.

  4. Kokotoa pembe ya awamu.

    Pembe ya Awamu=CB=90∘12=90∘×2=180∘\text{Pembe ya Awamu} = \frac{C}{B} = \frac{90^\circ}{\frac{1}{2}} = 90^\circ \times 2 = 180^\circ

    Kipindi ni 720∘\boxed{\text{720}^\circ} na pembe ya awamu ni 180∘\boxed{\text{180}^\circ}.

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