Solve the quadratic equation for Question 1.

Step 1: Solve the quadratic equation for Question 1.
The given equation is $x(x+2)-2=16$.
First, expand the left side of the equation:

$$x^2 + 2x - 2 = 16$$

Subtract 16 from both sides to set the equation to zero:

$$x^2 + 2x - 2 - 16 = 0$$ $$x^2 + 2x - 18 = 0$$

This is a quadratic equation in the form $ax^2+bx+c=0$, where $a=1$, $b=2$, and $c=-18$.
Use the quadratic formula $x = \frac{-b \pm