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Solve the quadratic equation x2 − 5x + 6 = 0 by completing the square.

Mathematics

ScanSolve AI Answer

Answer

x=2,x=3x=2, x=3

Step-by-step solution

6 steps
  1. Move the constant term to the right side of the equation.

    The given equation is x2−5x+6=0x^2 - 5x + 6 = 0.
    Subtract 6 from both sides:

    x2−5x=−6x^2 - 5x = -6
  2. Complete the square on the left side.

    To complete the square for an expression of the form x2+bxx^2 + bx, we add (b2)2(\frac{b}{2})^2.
    In this equation, b=−5b = -5.
    So, we need to add (−52)2=(254)(\frac{-5}{2})^2 = (\frac{25}{4}) to both sides.

  3. Add the value to both sides of the equation.

    x2−5x+254=−6+254x^2 - 5x + \frac{25}{4} = -6 + \frac{25}{4}
  4. Factor the left side as a perfect square trinomial and simplify the right side.

    The left side factors as (x−52)2(x - \frac{5}{2})^2.
    For the right side, find a common denominator: −6=−244-6 = -\frac{24}{4}.

    (x−52)2=−244+254(x - \frac{5}{2})^2 = -\frac{24}{4} + \frac{25}{4} (x−52)2=14(x - \frac{5}{2})^2 = \frac{1}{4}
  5. Take the square root of both sides.

    (x−52)2=±14\sqrt{\left(x - \frac{5}{2}\right)^2} = \pm\sqrt{\frac{1}{4}} x−52=±12x - \frac{5}{2} = \pm\frac{1}{2}
  6. Solve for xx.

    Add 52\frac{5}{2} to both sides:

    x=52±12x = \frac{5}{2} \pm \frac{1}{2}

    This gives two possible solutions:

    x1=52+12x_1 = \frac{5}{2} + \frac{1}{2} x1=62x_1 = \frac{6}{2} x1=3x_1 = 3

    And

    x2=52−12x_2 = \frac{5}{2} - \frac{1}{2} x2=42x_2 = \frac{4}{2} x2=2x_2 = 2

    The solutions are x=2,x=3x=2, x=3.

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