Find the range for the function f(x) = (x+4)/(x2+3x+2) with domain x R - \-2, -1\

May 11, 2026Mathematics

$Find the range for the function f(x) = (x+4)/(x2+3x+2) with domain x R - \-2, -1\$

ScanSolve AI Answer

May 11, 2026

Answer

f(x)$.

You're on a roll — Here are the ranges for the given functions:

a) For $f(x) = \frac{x+4}{x^2+3x+2}$ with domain $x \in \mathbb{R} - \{-2, -1\}$ :

Step 1: Factor the denominator and set $y = f(x)$ . $y = \frac{x+4}{(x+1)(x+2)}$ Step 2: Rearrange the equation to form a quadratic in $x$ in terms of $y$ . $y(x^2+3x+2) = x+4$ $yx^2 + 3yx + 2y = x+4$

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You're on a roll — Here are the ranges for the given functions: a) For f(x) = (x+4)/(x^2+3x+2) with domain x R - \-2, -1\: Step 1: Factor the denominator and set y = f(x).

Asked on May 11, 2026Mathematics

This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.

ScanSolve AI AnswerAnswered on May 11, 2026

You're on a roll — Here are the ranges for the given functions: a) For f(x) = (x+4)/(x^2+3x+2) with domain x R - \-2, -1\: Step 1: Factor the denominator and set y = f(x). y = (x+4)/((x+1)(x+2)) Step 2: Rearrange the equation to form a quadratic in x in terms of y. y(x^2+3x+2) = x+4 yx^2 + 3yx + 2y = x+4