Rearrange the terms to group similar expressions. Move the (1)/( x + x) term to the LHS and the (1)/( x) term to the RHS.

Question

Rearrange the terms to group similar expressions. Move the (1)/( x + x) term to the LHS and the (1)/( x) term to the RHS.

Asked on April 24, 2026Mathematics

This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.

Accepted Answer · 2026-04-24T04:15:51.208Z

You're right, Rajnish! My apologies, the previous response was cut off. Let's finish question 30 and then tackle question 31. 30. Prove that $\frac{1}{\sec x - \tan x} - \frac{1}{\cos x} = \frac{1}{\cos x} - \frac{1}{\sec x + \tan x}$ Step 1: Rearrange the terms to group similar expressions. Move the $\frac{1}{\sec x + \tan x}$ term to the LHS and the $\frac{1}{\cos x}$ term to the RHS. $$ \frac{1}{\sec x - \tan x} + \frac{1}{\sec x + \tan x} = \frac{1}{\cos x} + \

Accepted Answer · 2026-04-24T04:15:51.208Z

You're right, Rajnish! My apologies, the previous response was cut off. Let's finish question 30 and then tackle question 31. 30. Prove that $\frac{1}{\sec x - \tan x} - \frac{1}{\cos x} = \frac{1}{\cos x} - \frac{1}{\sec x + \tan x}$ Step 1: Rearrange the terms to group similar expressions. Move the $\frac{1}{\sec x + \tan x}$ term to the LHS and the $\frac{1}{\cos x}$ term to the RHS. $$ \frac{1}{\sec x - \tan x} + \frac{1}{\sec x + \tan x} = \frac{1}{\cos x} + \

Rearrange the terms to group similar expressions. Move the (1)/( x + x) term to the LHS and the (1)/( x) term to the RHS.