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Reduce the following ratios to their lowest terms: a) 300mL to 500mL b) 500g to 750g

Mathematics

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To reduce a ratio to its lowest terms, we express it as a fraction and then divide both parts by their greatest common divisor (GCD).

a) Reduce 300mL to 500mL

  1. Write the ratio as a fraction.

    300 mL500 mL\frac{300 \text{ mL}}{500 \text{ mL}}
  2. Divide both the numerator and the denominator by their greatest common divisor, which is 100.

    300÷100500÷100=35\frac{300 \div 100}{500 \div 100} = \frac{3}{5}

    The ratio in its lowest terms is 3:53:5.

    b) Reduce 500g to 750g

  3. Write the ratio as a fraction.

    500 g750 g\frac{500 \text{ g}}{750 \text{ g}}
  4. Divide both the numerator and the denominator by their greatest common divisor.

    We can start by dividing by 10.

    500÷10750÷10=5075\frac{500 \div 10}{750 \div 10} = \frac{50}{75}
  5. Divide both the numerator and the denominator by their new greatest common divisor, which is 25.

    50÷2575÷25=23\frac{50 \div 25}{75 \div 25} = \frac{2}{3}

    The ratio in its lowest terms is 2:32:3.

    Final Answers:

    a) 3:5\boxed{3:5}

    b) 2:3\boxed{2:3}

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