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Explain the relationship between gradients and y-intercepts of linear graphs, calculate the product of gradients, and plot the graphs.

Mathematics

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Step-by-step solution

3 steps

Here are the answers to the questions based on the image provided.

  1. Fill in the blanks regarding properties of linear graphs.

    • When the gradient is the same, the graphs are parallel to each other.
    • As the y-intercept increases, the graph shifts upwards.
    • Alternatively as the y-intercept decreases, the graph shifts downwards.
    • When the gradient is positive, the graphs increases.
  2. Calculate the product of the two gradients from the table.

    The table provides two equations and their gradients:

    • For y=2x+1y = 2x + 1, the gradient is m1=2m_1 = 2.
    • For y=−2x+1y = -2x + 1, the gradient is m2=−2m_2 = -2.

    The product of the two gradients is:

    m1×m2=2×(−2)=−4m_1 \times m_2 = 2 \times (-2) = -4

    The product of the two gradients is equal to −4\boxed{-4}.

  3. Plot the two graphs on one Cartesian Plane.

    We need to plot y=2x+1y = 2x + 1 and y=−2x+1y = -2x + 1.

    • For the graph y=2x+1y = 2x + 1:

      • The y-intercept is c=1c = 1, so the line passes through (0,1)(0, 1).
      • The gradient is m=2m = 2. From the y-intercept (0,1)(0, 1), move 1 unit to the right and 2 units up to find another point, (1,3)(1, 3).
      • Draw a straight line through (0,1)(0, 1) and (1,3)(1, 3).
    • For the graph y=−2x+1y = -2x + 1:

      • The y-intercept is c=1c = 1, so this line also passes through (0,1)(0, 1).
      • The gradient is m=−2m = -2. From the y-intercept (0,1)(0, 1), move 1 unit to the right and 2 units down to find another point, (1,−1)(1, -1).
      • Draw a straight line through (0,1)(0, 1) and (1,−1)(1, -1).

    Both lines intersect at the point (0,1)(0, 1).

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