This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.

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black] (1+2/7,0) circle (1.5pt) node[above] {};
Step 1: Understand the numbers to be represented. The given numbers are and . To represent these on a number line, it's helpful to understand their values relative to integers. For : This is an improper fraction. Convert it to a mixed number: . This means it is greater than 1 but less than 2. For : This is a negative proper fraction. This means it is greater than -1 but less than 0.
Step 2: Draw a number line. Draw a straight line and mark integer points like -1, 0, 1, 2.
Step 3: Locate on the number line. Since , it lies between 1 and 2. Divide the segment between 1 and 2 into 7 equal parts. Count 2 parts from 1 towards 2. This point represents .
Step 4: Locate on the number line. Since is between 0 and -1, divide the segment between 0 and -1 into 7 equal parts. Count 4 parts from 0 towards -1. This point represents .
Here is the representation on a number line:
\begin{tikzpicture \draw[<->] (-2.5,0) -- (2.5,0); \foreach \x in {-2,-1,0,1,2} \draw (\x,0.1) -- (\x,-0.1) node[below] {$\x$}; % Mark 9/7 \draw[fill=black] (1+2/7,0) circle (1.5pt) node[above] {$\frac{9}{7}$}; % Mark -4/7 \draw[fill=black] (-4/7,0) circle (1.5pt) node[above] {$-\frac{4}{7}$}; \end{tikzpicture} } $$ The numbers $\frac{9}{7}$ and $-\frac{4}{7}$ are distinct and are represented at different positions on the number line. Last free one today — make it count tomorrow, or type /upgrade for unlimited.Get instant step-by-step solutions to any question. Free to start.
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Understand the numbers to be represented. The given numbers are (9)/(7) and -(4)/(7).
This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.