This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.
ScanSolve AI Answer
Step 1: Rewrite the expression using logarithm properties.
The expression to evaluate is $\log_2 8 \sqrt{\frac{a^5 b}{c^3}}$.
Using the product rule of logarithms, $\log_x (MN) = \log_x M + \log_x N$:
$$ \log_2 8 + \log_2 \sqrt{\frac{a^5 b}{c^3}} $$
Rewrite the square root as a power: $\sqrt{X} = X^{\frac{1}{2}}$.
$$ \log_2 8 + \log_2 \left(\frac{a^5 b}{c^3}\right)^{\frac{1}{2}} $$
Step 2: Apply the power rule of logarithms.
Using the power rule, $\log_x M^P = P \log_x M$:
$$ \log_2 8 + \frac{1}{2} \log_2 \left(\frac{a^5 b}{c^3}\right) $$
Step 3: Apply the quotient and product rules of logarithms inside the parenthesis.
Using the quotient rule, $\log_x \left(\frac{M}{N}\right) = \log_x M - \log_x N$:
$$ \log_2 8 + \frac{1}{2} (\log_2 (a^5 b) - \log_2 (c^3)) $$
Using the product rule, $\log_x (MN) = \log_x M + \log_x N$:
$$ \log_2 8 + \frac{1}{2} (\log_2 a^5 + \log_2 b - \log_2 c^3) $$
Step 4: Apply the power rule again for $a^5$ and $c^3$.
$$ \log_2 8 + \frac{1}{2} (5 \log_2 a + \log_2 b - 3 \log_2 c) $$
Step 5: Evaluate $\log_2 8$.
Since $2^3 = 8$, we have $\log_2 8 = 3$.
Step 6: Substitute the given values into the expression.
Given:
$\log_2 a = 3$
$\log_2 b = -2$
$\log_2 c = 5$
Substitute these values into the expression from Step 4:
$$ 3 + \frac{1}{2} (5(3) + (-2) - 3(5)) $$
Step 7: Perform the arithmetic calculations.
$$ 3 + \frac{1}{2} (15 - 2 - 15) $$
$$ 3 + \frac{1}{2} (-2) $$
$$ 3 - 1 $$
$$ 2 $$
The final answer is $\boxed{2}$.
Rewrite the expression using logarithm properties.
|Mathematics
Rewrite the expression using logarithm properties.
ScanSolve AI Answer
Step 1: Rewrite the expression using logarithm properties.
The expression to evaluate is log28c3a5b.
Using the product rule of logarithms, logx(MN)=logxM+logxN:
log28+log2c3a5b
Rewrite the square root as a power: X=X21.
log28+log2(c3a5b)21
Step 2: Apply the power rule of logarithms.
Using the power rule, logxMP=PlogxM:
log28+21log2(c3a5b)
Step 3: Apply the quotient and product rules of logarithms inside the parenthesis.
Using the quotient rule, logx(NM)=logxM−logxN:
log28+21(log2(a5b)−log2(c3))
Using the product rule, logx(MN)=logxM+logxN:
log28+21(log2a5+log2b−log2c3)
Step 4: Apply the power rule again for a5 and c3.
log28+21(5log2a+log2b−3log2c)
Step 5: Evaluate log28.
Since 23=8, we have log28=3.
Step 6: Substitute the given values into the expression.
Given:
log2a=3log2b=−2log2c=5
Substitute these values into the expression from Step 4:
3+21(5(3)+(−2)−3(5))
Step 7: Perform the arithmetic calculations.
3+21(15−2−15)3+21(−2)3−12
The final answer is 2.
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