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Rewrite the expression using logarithm properties.

Mathematics

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Step-by-step solution

7 steps
  1. Rewrite the expression using logarithm properties.

    The expression to evaluate is log⁡28a5bc3\log_2 8 \sqrt{\frac{a^5 b}{c^3}}.
    Using the product rule of logarithms, log⁡x(MN)=log⁡xM+log⁡xN\log_x (MN) = \log_x M + \log_x N:

    log⁡28+log⁡2a5bc3\log_2 8 + \log_2 \sqrt{\frac{a^5 b}{c^3}}

    Rewrite the square root as a power: X=X12\sqrt{X} = X^{\frac{1}{2}}.

    log⁡28+log⁡2(a5bc3)12\log_2 8 + \log_2 \left(\frac{a^5 b}{c^3}\right)^{\frac{1}{2}}
  2. Apply the power rule of logarithms.

    Using the power rule, log⁡xMP=Plog⁡xM\log_x M^P = P \log_x M:

    log⁡28+12log⁡2(a5bc3)\log_2 8 + \frac{1}{2} \log_2 \left(\frac{a^5 b}{c^3}\right)
  3. Apply the quotient and product rules of logarithms inside the parenthesis.

    Using the quotient rule, log⁡x(MN)=log⁡xM−log⁡xN\log_x \left(\frac{M}{N}\right) = \log_x M - \log_x N:

    log⁡28+12(log⁡2(a5b)−log⁡2(c3))\log_2 8 + \frac{1}{2} (\log_2 (a^5 b) - \log_2 (c^3))

    Using the product rule, log⁡x(MN)=log⁡xM+log⁡xN\log_x (MN) = \log_x M + \log_x N:

    log⁡28+12(log⁡2a5+log⁡2b−log⁡2c3)\log_2 8 + \frac{1}{2} (\log_2 a^5 + \log_2 b - \log_2 c^3)
  4. Apply the power rule again for a5a^5 and c3c^3.

    log⁡28+12(5log⁡2a+log⁡2b−3log⁡2c)\log_2 8 + \frac{1}{2} (5 \log_2 a + \log_2 b - 3 \log_2 c)
  5. Evaluate log⁡28\log_2 8.

    Since 23=82^3 = 8, we have log⁡28=3\log_2 8 = 3.

  6. Substitute the given values into the expression.

    Given:
    log⁡2a=3\log_2 a = 3
    log⁡2b=−2\log_2 b = -2
    log⁡2c=5\log_2 c = 5
    Substitute these values into the expression from Step 4:

    3+12(5(3)+(−2)−3(5))3 + \frac{1}{2} (5(3) + (-2) - 3(5))
  7. Perform the arithmetic calculations.

    3+12(15−2−15)3 + \frac{1}{2} (15 - 2 - 15) 3+12(−2)3 + \frac{1}{2} (-2) 3−13 - 1 22
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