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Determine the rule of the mapping: x -> y where x = [3, 4, 5, 6, 7] and y = [8, 16, 32, 64, 128]

Mathematics

ScanSolve AI Answer

Answer

y=2xy = 2^x

Step-by-step solution

3 steps
  1. Analyze the given mapping pairs.

    We are given the following pairs of (x,y)(x, y) values:

    • When x=3x=3, y=8y=8
    • When x=4x=4, y=16y=16
    • When x=5x=5, y=32y=32
    • When x=6x=6, y=64y=64
    • When x=7x=7, y=128y=128
  2. Identify the relationship between xx and yy.

    Observe the yy values: 8,16,32,64,1288, 16, 32, 64, 128. These are all powers of 2.

    • 8=238 = 2^3
    • 16=2416 = 2^4
    • 32=2532 = 2^5
    • 64=2664 = 2^6
    • 128=27128 = 2^7
  3. Determine the rule of the mapping.

    By comparing the xx values with the exponents of 2 for the corresponding yy values, we can see a direct relationship:

    • For x=3x=3, y=23y=2^3
    • For x=4x=4, y=24y=2^4
    • For x=5x=5, y=25y=2^5
    • For x=6x=6, y=26y=2^6
    • For x=7x=7, y=27y=2^7 The rule of the mapping is y=2xy = 2^x.
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