Calculate the sample proportion (p).

Mathematics

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1. Determine a 98% confidence interval for the proportion for PDP in the population.

  1. Calculate the sample proportion (p^\hat{p}).

    The number of voters interviewed is n=1000n = 1000.
    The number of voters who support PDP is x=349x = 349.

    p^=xn=3491000=0.349\hat{p} = \frac{x}{n} = \frac{349}{1000} = 0.349
  2. Find the critical z-value (zα/2z_{\alpha/2}).

    For a 98% confidence interval, α=1−0.98=0.02\alpha = 1 - 0.98 = 0.02. So, α/2=0.01\alpha/2 = 0.01.
    The critical z-value corresponding to a cumulative probability of 1−0.01=0.991 - 0.01 = 0.99 is z0.01≈2.326z_{0.01} \approx 2.326.

  3. Calculate the standard error (SESE).

    SE=p^(1−p^)n=0.349(1−0.349)1000=0.349×0.6511000=0.2271991000=0.000227199≈0.01507SE = \sqrt{\frac{\hat{p}(1-\hat{p})}{n}} = \sqrt{\frac{0.349(1-0.349)}{1000}} = \sqrt{\frac{0.349 \times 0.651}{1000}} = \sqrt{\frac{0.227199}{1000}} = \sqrt{0.000227199} \approx 0.01507
  4. Calculate the margin of error (MEME).

    ME=zα/2×SE=2.326×0.01507≈0.03505ME = z_{\alpha/2} \times SE = 2.326 \times 0.01507 \approx 0.03505
  5. Construct the confidence interval.

    The confidence interval is p^±ME\hat{p} \pm ME.

    0.349±0.035050.349 \pm 0.03505 (0.349−0.03505,0.349+0.03505)(0.349 - 0.03505, 0.349 + 0.03505) (0.31395,0.38405)(0.31395, 0.38405)

    Rounding to three decimal places:

    (0.314,0.384)(0.314, 0.384)

    The 98% confidence interval for the proportion of PDP supporters is (0.314,0.384)\boxed{\mathbf{(0.314, 0.384)}}.

    2. Construct a 95% confidence interval for the proportion PP of defective items produced by the factory.

  6. Calculate the sample proportion (p^\hat{p}).

    The number of products sampled is n=75n = 75.
    The number of defective products is x=11x = 11.

    p^=xn=1175≈0.146667\hat{p} = \frac{x}{n} = \frac{11}{75} \approx 0.146667
  7. Find the critical z-value (zα/2z_{\alpha/2}).

    For a 95% confidence interval, α=1−0.95=0.05\alpha = 1 - 0.95 = 0.05. So, α/2=0.025\alpha/2 = 0.025.
    The critical z-value corresponding to a cumulative probability of 1−0.025=0.9751 - 0.025 = 0.975 is z0.025≈1.96z_{0.025} \approx 1.96.

  8. Calculate the standard error (SESE).

    SE=p^(1−p^)n=0.146667(1−0.146667)75=0.146667×0.85333375=0.12511175=0.00166814≈0.04084SE = \sqrt{\frac{\hat{p}(1-\hat{p})}{n}} = \sqrt{\frac{0.146667(1-0.146667)}{75}} = \sqrt{\frac{0.146667 \times 0.853333}{75}} = \sqrt{\frac{0.125111}{75}} = \sqrt{0.00166814} \approx 0.04084
  9. Calculate the margin of error (MEME).

    ME=zα/2×SE=1.96×0.04084≈0.08005ME = z_{\alpha/2} \times SE = 1.96 \times 0.04084 \approx 0.08005
  10. Construct the confidence interval.

    The confidence interval is p^±ME\hat{p} \pm ME.

    0.146667±0.080050.146667 \pm 0.08005 (0.146667−0.08005,0.146667+0.08005)(0.146667 - 0.08005, 0.146667 + 0.08005) (0.066617,0.226717)(0.066617, 0.226717)

    Rounding to three decimal places:

    (0.067,0.227)(0.067, 0.227)

    The 95% confidence interval for the proportion of defective items is (0.067,0.227)\boxed{\mathbf{(0.067, 0.227)}}.

    3. Compute a 96% confidence interval for the proportion of people who use Knorr Maggi cube.

  11. Calculate the sample proportion (p^\hat{p}).

    The number of people questioned is n=320n = 320.
    The number of people who answered 'yes' is x=82x = 82.

    p^=xn=82320=0.25625\hat{p} = \frac{x}{n} = \frac{82}{320} = 0.25625
  12. Find the critical z-value (zα/2z_{\alpha/2}).

    For a 96% confidence interval, α=1−0.96=0.04\alpha = 1 - 0.96 = 0.04. So, α/2=0.02\alpha/2 = 0.02.
    The critical z-value corresponding to a cumulative probability of 1−0.02=0.981 - 0.02 = 0.98 is z0.02≈2.054z_{0.02} \approx 2.054.

  13. Calculate the standard error (SESE).

    SE=p^(1−p^)n=0.25625(1−0.25625)320=0.25625×0.74375320=0.1905078125320=0.000595337≈0.02440SE = \sqrt{\frac{\hat{p}(1-\hat{p})}{n}} = \sqrt{\frac{0.25625(1-0.25625)}{320}} = \sqrt{\frac{0.25625 \times 0.74375}{320}} = \sqrt{\frac{0.1905078125}{320}} = \sqrt{0.000595337} \approx 0.02440
  14. Calculate the margin of error (MEME).

    ME=zα/2×SE=2.054×0.02440≈0.05011ME = z_{\alpha/2} \times SE = 2.054 \times 0.02440 \approx 0.05011
  15. Construct the confidence interval.

    The confidence interval is p^±ME\hat{p} \pm ME.

    0.25625±0.050110.25625 \pm 0.05011 (0.25625−0.05011,0.25625+0.05011)(0.25625 - 0.05011, 0.25625 + 0.05011) (0.20614,0.30636)(0.20614, 0.30636)

    Rounding to three decimal places:

    (0.206,0.306)(0.206, 0.306)

    The 96% confidence interval for the proportion of people who use Knorr Maggi cube is (0.206,0.306)\boxed{\mathbf{(0.206, 0.306)}}.

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