12 a. You have two metal tubes of the same diameter. Explain briefly how you can use the principles from thermal expansion of matter to fit one of the tubes into the other. b. With a labelled diagram, briefly how you can find the centre of mass of a regular shaped lamina which is rectangular in shape using straight edge apparatus.

Physics
12 a. You have two metal tubes of the same diameter. Explain briefly how you can use the principles from thermal expansion of matter to fit one of the tubes into the other. b. With a labelled diagram, briefly how you can find the centre of mass of a regular shaped lamina which is rectangular in shape using straight edge apparatus.

ScanSolve AI Answer

Answer

L \alpha_P \Delta T$.

12. (a)

Step 1: Select two metal tubes P and Q of identical diameter and same initial length LL. Tube P has known coefficient of linear expansion αP\alpha_P (e.g., steel tube, αP=11×106K1\alpha_P = 11 \times 10^{-6} \, K^{-1}). Tube Q has unknown coefficient αQ\alpha_Q.

Step 2: Fix one end of both tubes rigidly to a common support. Attach the free ends to a rigid crossbar or use a micrometer screw gauge to measure relative displacement δ\delta.

Step 3: Heat both tubes uniformly (e.g., with steam jacket), raising temperature by ΔT\Delta T (measured by thermometer in C^\circ\mathrm{C} or K\mathrm{K}).

The change in length for tube P: ΔLP=LαPΔT\Delta L_P = L \alpha_P \Delta T.

The change in length for tube Q: ΔLQ=LαQΔT\Delta L_Q = L \alpha_Q \Delta T.

Relative displacement: δ=ΔLQΔLP=L(αQαP)ΔT\delta = \Delta L_Q - \Delta L_P = L (\alpha_Q - \alpha_P) \Delta T.

Step 4: Solve for αQ\alpha_Q:

αQ=αP+δLΔT.\alpha_Q = \alpha_P + \frac{\delta}{L \Delta T}.

Units: δ\delta in m\mathrm{m}, LL in m\mathrm{m}, ΔT\Delta T in K\mathrm{K}, α\alpha in K1\mathrm{K}^{-1}.

This uses the principle of linear thermal expansion ΔL=LαΔT\Delta L = L \alpha \Delta T.

12. (b)

For a uniform rectangular lamina ABCD, the centre of mass (COM) is at the geometric centre.

Method using straight edge:

Step 1: Place lamina on white paper.

Step 2: Use straight edge to draw diagonal from corner A to C.

Step 3: Use straight edge to draw diagonal from corner B to D.

Step 4: Mark intersection point O — this is the COM.

Labelled diagram description:
Rectangle ABCD:

  • A top-left, B top-right, C bottom-right, D bottom-left.
  • Diagonal AC and BD cross at O (COM).

To verify with plumbline apparatus (using straight edge to mark lines):
Step 1: Punch three holes near edges (e.g., close to A, B, midway on CD).
Step 2: Suspend lamina from hole 1 via pin on stand; hang plumb bob, mark plumb line on paper using straight edge.
Step 3: Repeat for holes 2 and 3.
Step 4: Lines intersect at COM (same as O).

COM at intersection of diagonals or plumb lines.

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Quick Answer

12. (a) Step 1: Select two metal tubes P and Q of identical diameter and same initial length L.

12 a. You have two metal tubes of the same diameter. Explain briefly how you can use the principles from thermal expansion of matter to fit one of the tubes into the other. b. With a labelled diagram, briefly how you can find the centre of mass of a regular shaped lamina which is rectangular in shape using straight edge apparatus.
Physics

This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.

ScanSolve AI Answer
12. (a) Step 1: Select two metal tubes P and Q of identical diameter and same initial length L. Tube P has known coefficient of linear expansion _P (e.g., steel tube, _P = 11 × 10^-6 \, K^-1). Tube Q has unknown coefficient _Q. Step 2: Fix one end of both tubes rigidly to a common support. Attach the free ends to a rigid crossbar or use a micrometer screw gauge to measure relative displacement . Step 3: Heat both tubes uniformly (e.g., with steam jacket), raising temperature by T (measured by thermometer in ^ or K). The change in length for tube P: L_P = L _P T. The change in length for tube Q: L_Q = L _Q T. Relative displacement: = L_Q - L_P = L (_Q - _P) T. Step 4: Solve for _Q: _Q = _P + ()/(L T). Units: in m, L in m, T in K, in K^-1. This uses the principle of linear thermal expansion L = L T. 12. (b) For a uniform rectangular lamina ABCD, the centre of mass (COM) is at the geometric centre. Method using straight edge: Step 1: Place lamina on white paper. Step 2: Use straight edge to draw diagonal from corner A to C. Step 3: Use straight edge to draw diagonal from corner B to D. Step 4: Mark intersection point O — this is the COM. Labelled diagram description: Rectangle ABCD: A top-left, B top-right, C bottom-right, D bottom-left. Diagonal AC and BD cross at O (COM). To verify with plumbline apparatus (using straight edge to mark lines): Step 1: Punch three holes near edges (e.g., close to A, B, midway on CD). Step 2: Suspend lamina from hole 1 via pin on stand; hang plumb bob, mark plumb line on paper using straight edge. Step 3: Repeat for holes 2 and 3. Step 4: Lines intersect at COM (same as O). COM at intersection of diagonals or plumb lines.