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Simplify (32x10)^(1/6)

Mathematics

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Step-by-step solution

4 steps

let's simplify this expression using the rules of indices.

The problem is (32x10)15(32x^{10})^{\frac{1}{5}}. We need to apply the exponent 15\frac{1}{5} to both the numerical coefficient and the variable term inside the parentheses.

  1. Apply the exponent to each factor inside the parentheses.

    (32x10)15=3215⋅(x10)15(32x^{10})^{\frac{1}{5}} = 32^{\frac{1}{5}} \cdot (x^{10})^{\frac{1}{5}}
  2. Evaluate 321532^{\frac{1}{5}}.

    This means finding the fifth root of 32.
    We know that 2×2×2×2×2=322 \times 2 \times 2 \times 2 \times 2 = 32.
    So, 3215=232^{\frac{1}{5}} = 2.

  3. Evaluate (x10)15(x^{10})^{\frac{1}{5}} using the power of a power rule (am)n=am×n(a^m)^n = a^{m \times n}.

    (x10)15=x10×15=x105=x2(x^{10})^{\frac{1}{5}} = x^{10 \times \frac{1}{5}} = x^{\frac{10}{5}} = x^2
  4. Combine the simplified terms.

    2⋅x2=2x22 \cdot x^2 = 2x^2

    The simplified expression is ∗2x2\boxed*{2x^2}.

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