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Simplify: a) 1/(m-n) - (m+n)/(m2-n2) b) (x+1)/(x+2) + (x-2)/(x2-4) c) 4x/(x2-1) - (x+1)/(x-1) d) (a2+1)/(a+1) + (a2-a+1)/(a2-1) e) x/(x+y) - xy/(x2+2xy+y2) f) 1/(a-x) + x/(a2-2ax+x2)

Mathematics

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यहाँ दिइएको व्यञ्जकलाई सरल बनाउनुपर्छ:

1(x−3)(x+2)+3(x+2)(x−4)−2(x−3)(x−4)\frac{1}{(x-3)(x+2)} + \frac{3}{(x+2)(x-4)} - \frac{2}{(x-3)(x-4)}
  1. सबै भिन्नहरूको साझा हर (common denominator) पत्ता लगाउनुहोस्।

    दिएका हरहरू (x−3)(x+2)(x-3)(x+2), (x+2)(x−4)(x+2)(x-4), र (x−3)(x−4)(x-3)(x-4) हुन्। यिनीहरूको लघुत्तम समापवर्त्य (LCM) (x−3)(x+2)(x−4)(x-3)(x+2)(x-4) हुन्छ।

  2. प्रत्येक भिन्नलाई साझा हरमा रूपान्तरण गर्नुहोस्।

    पहिलो भिन्न:

    1(x−3)(x+2)=1⋅(x−4)(x−3)(x+2)(x−4)=x−4(x−3)(x+2)(x−4)\frac{1}{(x-3)(x+2)} = \frac{1 \cdot (x-4)}{(x-3)(x+2)(x-4)} = \frac{x-4}{(x-3)(x+2)(x-4)}

    दोस्रो भिन्न:

    3(x+2)(x−4)=3⋅(x−3)(x+2)(x−4)(x−3)=3(x−3)(x−3)(x+2)(x−4)\frac{3}{(x+2)(x-4)} = \frac{3 \cdot (x-3)}{(x+2)(x-4)(x-3)} = \frac{3(x-3)}{(x-3)(x+2)(x-4)}

    तेस्रो भिन्न:

    2(x−3)(x−4)=2⋅(x+2)(x−3)(x−4)(x+2)=2(x+2)(x−3)(x+2)(x−4)\frac{2}{(x-3)(x-4)} = \frac{2 \cdot (x+2)}{(x-3)(x-4)(x+2)} = \frac{2(x+2)}{(x-3)(x+2)(x-4)}
  3. सबै भिन्नहरूलाई साझा हरमा जोड्नुहोस् र घटाउनुहोस्।

    (x−4)+3(x−3)−2(x+2)(x−3)(x+2)(x−4)\frac{(x-4) + 3(x-3) - 2(x+2)}{(x-3)(x+2)(x-4)}
  4. अंश (numerator) लाई सरल बनाउनुहोस्।

    अंश =(x−4)+3(x−3)−2(x+2)= (x-4) + 3(x-3) - 2(x+2)
    अंश =x−4+3x−9−(2x+4)= x - 4 + 3x - 9 - (2x + 4)
    अंश =x−4+3x−9−2x−4= x - 4 + 3x - 9 - 2x - 4
    समान पदहरूलाई जोड्नुहोस्:
    अंश =(x+3x−2x)+(−4−9−4)= (x + 3x - 2x) + (-4 - 9 - 4)
    अंश =(4x−2x)+(−13−4)= (4x - 2x) + (-13 - 4)
    अंश =2x−17= 2x - 17

  5. अन्तिम परिणाम लेख्नुहोस्।

    2x−17(x−3)(x+2)(x−4)\frac{2x - 17}{(x-3)(x+2)(x-4)}

    अतः, सरल बनाउँदा प्राप्त हुने मान 2x−17(x−3)(x+2)(x−4)\frac{2x - 17}{(x-3)(x+2)(x-4)} हो।

    The simplified expression is 2x−17(x−3)(x+2)(x−4)\boxed{\frac{2x - 17}{(x-3)(x+2)(x-4)}}.

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