Simplify log 6 - log 15 + 2 log 5 and log (5/8) - 2 log (5/9) + log 40

$n \log a = \log (a^n)$.

$\log a + \log c = \log (a \cdot c)$.

Final answer: $b = 375$
375

2)

$n \log a = \log (a^n)$.

$-\log \frac{9}{49} = \log \frac{49}{9}$.

$\log a + \log b + \log c = \log (a \cdot b \cdot c)$.

First, $\frac{5}{3} \cdot \frac{49}{9}$.
Numerator: $5 \cdot 49 = 245$
Denominator: $3 \cdot 9 = 27$

Final answer: $\log \frac{10780}{27}$
\log \dfrac{10780}{27}