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Simplify the expression: (12dn3)/(15cd3) / (9c3n)/(10c2d2)

Mathematics

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Answer

8n29c2\frac{8n^2}{9c^2}

Step-by-step solution

6 steps

To simplify the expression, we will first convert the division into multiplication by taking the reciprocal of the second fraction.

  1. Rewrite the division as multiplication.

    12dn315cd3÷9c3n10c2d2=12dn315cd3×10c2d29c3n\frac{12dn^3}{15cd^3} \div \frac{9c^3n}{10c^2d^2} = \frac{12dn^3}{15cd^3} \times \frac{10c^2d^2}{9c^3n}
  2. Multiply the numerators and the denominators.

    12dn3×10c2d215cd3×9c3n\frac{12dn^3 \times 10c^2d^2}{15cd^3 \times 9c^3n}
  3. Group the numerical coefficients and the variables.

    (12×10)×(d⋅d2)×(n3)×(c2)(15×9)×(c⋅c3)×(d3)×(n)\frac{(12 \times 10) \times (d \cdot d^2) \times (n^3) \times (c^2)}{(15 \times 9) \times (c \cdot c^3) \times (d^3) \times (n)} 120d1+2n3c2135c1+3d3n\frac{120 d^{1+2} n^3 c^2}{135 c^{1+3} d^3 n} 120d3n3c2135c4d3n\frac{120 d^3 n^3 c^2}{135 c^4 d^3 n}
  4. Simplify the numerical coefficients by dividing by their greatest common divisor, which is 15.

    120÷15135÷15=89\frac{120 \div 15}{135 \div 15} = \frac{8}{9}
  5. Simplify the variables using the exponent rule xaxb=xa−b\frac{x^a}{x^b} = x^{a-b}.

    For dd: d3d3=d3−3=d0=1\frac{d^3}{d^3} = d^{3-3} = d^0 = 1
    For nn: n3n=n3−1=n2\frac{n^3}{n} = n^{3-1} = n^2
    For cc: c2c4=c2−4=c−2=1c2\frac{c^2}{c^4} = c^{2-4} = c^{-2} = \frac{1}{c^2}

  6. Combine the simplified numerical and variable parts.

    89×1×n2×1c2=8n29c2\frac{8}{9} \times 1 \times n^2 \times \frac{1}{c^2} = \frac{8n^2}{9c^2}

    The simplified expression is:

    8n29c2\frac{8n^2}{9c^2}
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