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Simplify the expression: (3)/(x+1) - (2)/(x+2)

Mathematics

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Answer

x+4(x+1)(x+2)\frac{x+4}{(x+1)(x+2)}

Step-by-step solution

7 steps
  1. Identify the expression to simplify.

    The expression is given as:

    3x+1−2x+2\frac{3}{x+1} - \frac{2}{x+2}
  2. Find a common denominator for the two fractions.

    The common denominator is the product of the individual denominators: (x+1)(x+2)(x+1)(x+2).

  3. Rewrite each fraction with the common denominator.

    To get the common denominator for the first fraction, multiply its numerator and denominator by (x+2)(x+2):

    3x+1=3(x+2)(x+1)(x+2)\frac{3}{x+1} = \frac{3(x+2)}{(x+1)(x+2)}

    To get the common denominator for the second fraction, multiply its numerator and denominator by (x+1)(x+1):

    2x+2=2(x+1)(x+1)(x+2)\frac{2}{x+2} = \frac{2(x+1)}{(x+1)(x+2)}
  4. Subtract the fractions.

    Now that both fractions have the same denominator, subtract their numerators:

    3(x+2)(x+1)(x+2)−2(x+1)(x+1)(x+2)=3(x+2)−2(x+1)(x+1)(x+2)\frac{3(x+2)}{(x+1)(x+2)} - \frac{2(x+1)}{(x+1)(x+2)} = \frac{3(x+2) - 2(x+1)}{(x+1)(x+2)}
  5. Expand the numerator.

    Distribute the numbers into the parentheses in the numerator:

    3(x+2)−2(x+1)=(3x+6)−(2x+2)3(x+2) - 2(x+1) = (3x + 6) - (2x + 2)
  6. Simplify the numerator by combining like terms.

    3x+6−2x−2=(3x−2x)+(6−2)=x+43x + 6 - 2x - 2 = (3x - 2x) + (6 - 2) = x + 4
  7. Write the simplified expression as a single fraction.

    x+4(x+1)(x+2)\frac{x+4}{(x+1)(x+2)}

    The denominator can also be expanded:

    (x+1)(x+2)=x2+2x+x+2=x2+3x+2(x+1)(x+2) = x^2 + 2x + x + 2 = x^2 + 3x + 2

    So, the expression can also be written as:

    x+4x2+3x+2\frac{x+4}{x^2+3x+2}
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