This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.

ScanSolve AI Answer
Answer
-4i
Here are the simplified forms of the complex numbers:
a) Simplify
Step 1: Multiply the numerator and denominator by to eliminate from the denominator.
Step 2: Perform the multiplication and use the identity . The simplified form is .
b) Simplify
Step 1: Multiply the numerator and denominator by the conjugate of the denominator, which is .
Step 2: Expand the numerator and the denominator. Numerator: Denominator:
Step 3: Combine the simplified numerator and denominator. The simplified form is .
c) Simplify
Step 1: Multiply the numerator and denominator by the conjugate of the denominator, which is .
Step 2: Expand the numerator and the denominator. Numerator: Denominator:
Step 3: Combine the simplified numerator and denominator. The simplified form is \boxed{-\frac{1{61} + \frac{50}{61}i}}.
d) Simplify
Step 1: Expand the denominator .
Step 2: Rewrite the expression with the expanded denominator.
Step 3: Multiply the numerator and denominator by the conjugate of the new denominator, which is .
Step 4: Expand the numerator and the denominator. Numerator: Denominator:
Step 5: Combine the simplified numerator and denominator. The simplified form is \boxed{\frac{16{25} - \frac{12}{25}i}}.
What's next?
Get instant step-by-step solutions to any question. Free to start.
Ask Your Question
Handwritten Step-by-Step Solution
Get this as a handwritten image on WhatsApp — like a tutor wrote it for you.
Try on WhatsAppStill have questions?
a) Simplify (4)/(i) Step 1: Multiply the numerator and denominator by i to eliminate i from the denominator.
This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.